Don't we sub in t1 approximation from part i)?
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Since largest co-efficient is x^{4n-2k}, we cannot go beyond k=n in order to maintain x^{2n} co-efficient
Add all side by side
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Hopefully that is correct
YepDon't we sub in t1 approximation from part i)?
r is a variable thoughfor the water droplet
Can you integrate the dV/dt -> and you get like v = (-10^-4)(4.pi.r^2)t + c
Sub in conditions
Sub in r (from subbing in V in the formula volume formula given) to get the answer
Lol that's what I did. What was ur answer though ?for the water droplet
Can you integrate the dV/dt -> and you get like v = (-10^-4)(4.pi.r^2)t + c
Sub in conditions
Sub in r (from subbing in V in the formula volume formula given) to get the answer
I got to the point that a=-9x, but didn't write a concluding statement that the period would be 2pi/3
If your final answer is equivalent then you won't lose the markfor the solution the f)
Would you lose a mark if you didn't factorise out the 1/3?
Of course not.for the solution the f)
Would you lose a mark if you didn't factorise out the 1/3?
You can leave it in exact formfor 11f) did you have to type the actual calculator value or can you leave it as 1/3 (arctane - pi/4).