For question 4 (iii) area of triangle = 4x , let the base be x.
use the equation from (ii) area = 8 + x + square root of 8 square + x square
equate the two , 4x = 8 + x + square root of (8 square + x sqaure)
(3x - 8) square = 8 square + x square
9x sqaure - 48x + 64 -x sqaure - 64= 0
8x sqaure - 48x = 0
divide both side by 8
x sqaure -6x=0
x ( x - 6) = 0
Since x is not zero , soo x is equal to 6.
for (iv) using the x we found , and using that right angle triagle , we can easily found the 3 side of the triangle. (patho therom)
i found them to be 10 , 17 and 9
and i found the area , by completing the graph into a rectangle, then minus the two corner triagnle and divide them by 2.
and i remember i found it to be 36.
soo 36 = Half Pr
72 = Pr
and adding 10,17AND 9 = u again get 36
So 72 = 36 r
So r =2 .
This is how i get 2. i dont think its 3. . .
*gosh , u guys reply fast @@ I did it the stupid"ish" way, still works >_>