Qs in complex number (1 Viewer)

[rheno]

Solve:
cos^2 ax^2 +sin2ax + 1= 0


i'm just starting on complex number...can u help me solve this question, plz?

 

[pLuvia]

Use quadratic formula and it should yield something nice

After you use the formula and simplify you should get this
x=-sin2a+icosa

 

[rheno]

i know that i should use quadratic formula, but i can not solve it......i'm really stuck ...but the answer is -tan a+- i
i dunno how to get the answer...can u plz show me???

 

[Bank$]

use the sub cos^2(ax) = 1-sin^2(ax) then make it into the form:

ax^2 + bx + c=0 (with the sub that x=sinax)

then find sinax with the formula:

minus b plus or minus sq. root of b squared minus 4 times "a" times "c" over 2a.

then do the 2k(pie) thing

 

[vafa]

Solution:
View attachment 14877