Quadratic Equation Help (1 Viewer)

Lukybear · May 13, 2009

This is tearing my brains out:

((-p-12)/6)^2 + 4((-p-12)/6) + 4 = 0

Dont solve by sub for ((-p-12)/6)=u

Please solve by expanding and post working out. Did any1 get p^2-120=0 when expanded?

study-freak · May 13, 2009

well, no time to post working out but p=0 when you expand it.

Air Jordan · May 13, 2009

$(\frac{-p -12}{6})^{2} + 4(\frac{-p-12}{6})+4 = 0$
$(\frac{p^{2}+24p+144}{36}) + (\frac{-4(p+12)}{6})+\frac{144}{36} = 0$
$\frac{p^{2}+24p+144}{36} + \frac{-24(p+12)}{36}+\frac{144}{36} = 0$
$p^{2} + 24p + 144 -24p -288 + 144 = 0$
$p^{2} = 0$
$p=0$

Timothy.Siu · May 13, 2009

why would u solve by expanding

Air Jordan · May 13, 2009

Lukybear said:
This is tearing my brains out:

((-p-12)/6)^2 + 4((-p-12)/6) + 4 = 0

Dont solve by sub for ((-p-12)/6)=u

Please solve by expanding and post working out. Did any1 get p^2-120=0 when expanded?

...

random-1005 · May 13, 2009

Lukybear said:
This is tearing my brains out:

((-p-12)/6)^2 + 4((-p-12)/6) + 4 = 0

Dont solve by sub for ((-p-12)/6)=u

Please solve by expanding and post working out. Did any1 get p^2-120=0 when expanded?

'
your actually stupid enough to expand it, a question would never specify that, actually read the question before you do, make a judgement, is it a worthwile question?, no its not

Lukybear · May 13, 2009

Thxs air jordan. I had one of those bad brain periods... couldnt do it via expansion...

Quadratic Equation Help (1 Viewer)

Lukybear

Active Member

study-freak

Bored of

Air Jordan

Member

Timothy.Siu

Prophet 9

Air Jordan

Member

random-1005

Banned

Lukybear

Active Member

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