ToRnaDo
Member
iii) we did prove it in part i) and ii) that
h = v^2sin^2 a / 2g and x = v^2 sin2a /g
should notice that the maximum height in part iii) is H-S = h
soo H-S = v^2 sin^2 a/ 2g (1) and d= v^2 sin2a/g
= 2v^2 sina cosa/g
--> d^2 = 4 v^4 sin^2 a cos^2 a / g^2 (2)
sub (1) into (2) to withdraw v^2 cos^2 = something
And from (1) again to withdraw v^2 sin^2 = somthing
Using fact that sin^2 + cos^2 = 1 to add them together
Should end up with equation relative to d and (H-S) and find out result easily..... That what i think the answer will be
Just give me 10 minutes more ..... but actually i lost about 7 marks for silly mistake and included the 4 marks question 7 iii)
Grrrr Hope i still get in band 6. I already did badly in 4 Units> Soo please BOS ..Don't find our any more my silly mistake
h = v^2sin^2 a / 2g and x = v^2 sin2a /g
should notice that the maximum height in part iii) is H-S = h
soo H-S = v^2 sin^2 a/ 2g (1) and d= v^2 sin2a/g
= 2v^2 sina cosa/g
--> d^2 = 4 v^4 sin^2 a cos^2 a / g^2 (2)
sub (1) into (2) to withdraw v^2 cos^2 = something
And from (1) again to withdraw v^2 sin^2 = somthing
Using fact that sin^2 + cos^2 = 1 to add them together
Should end up with equation relative to d and (H-S) and find out result easily..... That what i think the answer will be
Just give me 10 minutes more ..... but actually i lost about 7 marks for silly mistake and included the 4 marks question 7 iii)
Grrrr Hope i still get in band 6. I already did badly in 4 Units> Soo please BOS ..Don't find our any more my silly mistake
