B bos1234 Member Joined Oct 9, 2006 Messages 491 Gender Male HSC 2007 Apr 12, 2007 #1 The angle of inclination (a) and the y-intercept A of a line a given. Use the formula gradient = tana to find the gradient of each line, then find its eqn a=145 degrees, A=(0,1) answer : x+y - 1 = 0 ??????????????????
The angle of inclination (a) and the y-intercept A of a line a given. Use the formula gradient = tana to find the gradient of each line, then find its eqn a=145 degrees, A=(0,1) answer : x+y - 1 = 0 ??????????????????
onebytwo Recession '08 Joined Apr 19, 2006 Messages 823 Location inner west Gender Male HSC 2006 Apr 13, 2007 #2 bos1234 said: The angle of inclination (a) and the y-intercept A of a line a given. Use the formula gradient = tana to find the gradient of each line, then find its eqn a=145 degrees, A=(0,1) answer : x+y - 1 = 0 ?????????????????? Click to expand... hmm, im assuming they mean a=135degs then it would make sense
bos1234 said: The angle of inclination (a) and the y-intercept A of a line a given. Use the formula gradient = tana to find the gradient of each line, then find its eqn a=145 degrees, A=(0,1) answer : x+y - 1 = 0 ?????????????????? Click to expand... hmm, im assuming they mean a=135degs then it would make sense
B bos1234 Member Joined Oct 9, 2006 Messages 491 Gender Male HSC 2007 Apr 13, 2007 #3 ohy kk.. i think they mistyped the question thanks bye
