A window frame consists of 6 equal rectangles.
Only 12 m of frame is available for it's construction.
Find it's maximum area and hence, the dimensions of the frame for which the area of the window is a max.
![Screen Shot 2016-10-15 at 8.27.14 pm.png](/data/attachments/25/25814-12194a6157075108ce6d172c787db6ff.jpg)
I presume the '12 m of frame available for construction' is the material required for the perimeter of the window frame, but I cannot come up with a correct equation suitable to equate to 12m (eg. 9l + 8w =12) [which is wrong]
Only 12 m of frame is available for it's construction.
Find it's maximum area and hence, the dimensions of the frame for which the area of the window is a max.
![Screen Shot 2016-10-15 at 8.27.14 pm.png](/data/attachments/25/25814-12194a6157075108ce6d172c787db6ff.jpg)
I presume the '12 m of frame available for construction' is the material required for the perimeter of the window frame, but I cannot come up with a correct equation suitable to equate to 12m (eg. 9l + 8w =12) [which is wrong]