N Nosviper Member Joined Oct 12, 2006 Messages 55 Gender Female HSC 2007 Oct 11, 2007 #1 Does anybody know how to solve this. Engineering Studies John Rochford PAge 4-7 Question (ii)
J jayraad New Member Joined Nov 30, 2006 Messages 10 Gender Male HSC 2007 Oct 12, 2007 #2 Hi, first you find the VR of the "teeth" so 56/20= 2.8 VR= dE/dL dE= 2 x pI x 180 = 1130.97 dL= 2 x pI x 300 x ( VR of the "teeth" in this case 2.8 ) = 5277.88 Therefore 1130.97/5277.88 = 0.214 Hope it helped Good Luck!
Hi, first you find the VR of the "teeth" so 56/20= 2.8 VR= dE/dL dE= 2 x pI x 180 = 1130.97 dL= 2 x pI x 300 x ( VR of the "teeth" in this case 2.8 ) = 5277.88 Therefore 1130.97/5277.88 = 0.214 Hope it helped Good Luck!
