Roots of Unity? (1 Viewer)

Joined
Oct 23, 2005
Messages
116
Location
Fairfield West
Gender
Male
HSC
N/A
Can someone explain how to do this question? :)


1, w and w^2 are the three cube roots of unity. State the values of w^3 and 1 + w + w^2. Hence simplify each of the expressions (1 + 3w + w^2)^2 and (1 + w + 3w^2)^2 and show that their sum is -4 and their product is 16.

(also, why do we call them roots of unity?)
 

ninetypercent

ninety ninety ninety
Joined
May 23, 2009
Messages
2,148
Location
Sydney
Gender
Female
HSC
2010
unity meaning 1. roots of unity = roots of one

if w is a cube root of unity, then
w^3 = 1

w^3 -1 = 0
(w-1)(w^2 + w +1) = 0
(w^2 + w +1) = 0 (if w is not equal to 1)

(1 + 3w + w^2)^2 = (-w + 3w)^2 = (2w)^2 = 4w^2

(1 + w + 3w^2)^2 = (-w^2 + 3w^2)^2 = (2w^2)^2 = 4w^4 = 4w

sum of them = 4w + 4w^2 = 4(w+w^2) = 4(-1) = -4

product of them = 4w^2(4w) = 16w^3 = 16
 

fullonoob

fail engrish? unpossible!
Joined
Jul 19, 2008
Messages
465
Gender
Male
HSC
2010
(1 + 3w + w^2)^2 = (-w + 3w)^2 = (2w)^2 = 4w^2

(1 + w + 3w^2)^2 = (-w^2 + 3w^2)^2 = (2w^2)^2 = 4w^4 = 4w

can please explain this step, i don't see it
 

fullonoob

fail engrish? unpossible!
Joined
Jul 19, 2008
Messages
465
Gender
Male
HSC
2010
rofl dw got it now LOL
but dont get where you obtain (-w + 3w)^2 from
i just did since (w^2 + w +1) = 0
(0+2w)^2 = 4w^2
same for the other one
 
Last edited:

bachviete

Member
Joined
Oct 24, 2009
Messages
53
Gender
Undisclosed
HSC
N/A
(1 + 3w + w^2)^2 = (-w + 3w)^2 = (2w)^2 = 4w^2

(1 + w + 3w^2)^2 = (-w^2 + 3w^2)^2 = (2w^2)^2 = 4w^4 = 4w

can please explain this step, i don't see it
You have to know these two rules





ie


These are explained in both Excel MX2 and Cambridge (i think)

So



and




EDIT: See you got it =)
 

fullonoob

fail engrish? unpossible!
Joined
Jul 19, 2008
Messages
465
Gender
Male
HSC
2010
You have to know these two rules





ie


These are explained in both Excel MX2 and Cambridge (i think)

So



and




EDIT: See you got it =)
umm thats not really my question :p
(1 + 3w + w^2)^2 = >>>>>(-w + 3w)^2<<<< = (2w)^2 = 4w^2

(1 + w + 3w^2)^2 = >>>>(-w^2 + 3w^2)^2<<<< = (2w^2)^2 = 4w^4 = 4w
where does he get this. Probs another method but dno what it is :spin:
 

bachviete

Member
Joined
Oct 24, 2009
Messages
53
Gender
Undisclosed
HSC
N/A
umm thats not really my question :p
(1 + 3w + w^2)^2 = >>>>>(-w + 3w)^2<<<< = (2w)^2 = 4w^2

(1 + w + 3w^2)^2 = >>>>(-w^2 + 3w^2)^2<<<< = (2w^2)^2 = 4w^4 = 4w
where does he get this. Probs another method but dno what it is :spin:
Allow me to explain ;P lol





;)
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top