SDD: Multiple Choice (4 Viewers)

[dv3]

How did you guys go in the multiple choice? Please post your answers so we can compare.

 

[vociferocity]

man, as if I remember how I answered these

 

[Nivek5]

1|A
2|C
3|D
4B
5|B
6|C
7|B
8|D
9|C
10|B
11|C
12|A
13|D
14|B
15|B
16|B
17|B
18|A
19|C
20|D

I know there are mistakes as i generally didnt know the answer

 

[robm]

1)a
2)c
3)d
4)b
5)b
6)c
7)d
8)d
9)b
10)c
11)c
12)a
13)d
14)c
15)b
16)b
17)c
18)a
19)c
20)a


k now other people post up theirs, regardless of what you got

 

[Snoople]

i spent heaps of MC cutting down stupid answrs and picking randomly out of ones i had lol and i got 16 wrong lol..
i put C.. such a tard

 

[dv3]

1 a
2 c
3 d
4 b
5 b
6 c
7 d
8 d
9 a (mainly because its little code which could simply show a message to check if the module has passed correctly......i was tossing between a and b and decided to go a lol ----probably wrong though)
10 b
11 c
12 a
13 d
14 c
15 b
16 b
17 c
18 a
19 c
20 a (guessed)

 

[Nivek5]

20 = D

Cant be found = true cuz there is no checks for Found = True so it would be useless

If target = index it would have to continue through the whole array.. say it was 5000 index long.. and you found it on index 50... you would have to go through 4950 more indexs for no reason

No need to print

Has to be D = Index=Lengthofarray.

So next pass it will end.

=]

 

[mik e]

I dont know how well i did(Im not a uber geek so yeah) but this is what i got
1.A
2.C
3.D
4.B
5.B
6.C
7.A
8.A
9.C
10.D
11.A
12.D
13.D
14.C
15.B
16.C
17.A
18.B
19.C
20.D

And is there a way to find out the answers???

 

[joshhunt]

1) a
2) c
3) d
4) b
5) b
6) c
7) d
8) d
9) b
10) b
11) c
12) a
13) d
14) b
15) b
16) FORGOT TO GO BACK AND ANSWER!!!!11ONE
17) c
18) a
19) c
20) b - I really didnt like this question. I think A, B and D all should have been in there. I suppose B answered the question better… I think (the question was very vague)

 

[mystiques4]

I got A for 11.
C seemed wrong... I thought the brackets meant variables being passed from module to module, not data being read?

 

[mik e]

Yeah i got A aswell it sounded right i hope.

 

[NitroBoon]

I got:
1) A
2) C
3) D
4) B
5) B
6) C
7) D
8) D
9) B
10) B
11) C
12) A
13) D
14) C
15) A
16) B
17) C
18) A
19) C
20) A

 

[51684]

1. A
2. C
3. D
4. B
5. B
6. C
7. D
8. D
9. B
10. B
11. C
12. A
13. D
14. C
15. No idea.
16. B
17. C
18. A
19. C
20. D

 

[lolrofllol]

1. A
2. C
3. D
4. B
5. B
6. C
7. D
8. C (teacher said D)
9. B
10. B
11. C
12. A
13. D
14. C
15. B (not sure)
16. B
17. C
18. A
19. C
20. D

Fair test...

 

[Handmedown]

Yeah 8 would have been D in my opinion. It wasn't C however, as DLLs are included after compilation in a process called linking.

15 would have been A. If you were to imagine M1 calling M2 the line would have been:

M2 (a,b) as a and b were the names of the parameter and control parameter/flag between the two.

Hence the first line would have been:

BEGIN SUBPROGRAM M2 (a,b)

 

[Mr-Morten]

15 would have been A. If you were to imagine M1 calling M2 the line would have been:

M2 (a,b) as a and b were the names of the parameter and control parameter/flag between the two.

Hence the first line would have been:

BEGIN SUBPROGRAM M2 (a,b)

I put B, but technically I can't see that any of the answers are correct. C and D are obviously wrong so that leaves A and B. With A, b isn't a paramater passed to M2, its a value returned to M1. Hence it shouldn't be in the first line as a parameter for M2. With B, a and d are both passed to M2, but d still shouldn't be a parameter for M2 as it's supposedly the return from a call made to M4.

That's how I see it anyway. Can anyone else shed any light on this?

 

[sidereal]

I put B, but technically I can't see that any of the answers are correct. C and D are obviously wrong so that leaves A and B. With A, b isn't a paramater passed to M2, its a value returned to M1. Hence it shouldn't be in the first line as a parameter for M2. With B, a and d are both passed to M2, but d still shouldn't be a parameter for M2 as it's supposedly the return from a call made to M4.

That's how I see it anyway. Can anyone else shed any light on this?

this comes back to the stupid way the HSC psuedocode works. according to the specifications, there's no psuedocode instruction to "return" a value. instead they like to use a parameter in the subprogram that is assumed to be passed by reference. so something like:

BEGIN MAINLINE
	a = "hello"
	doStuff(a, b)
	PRINT b
END MAINLINE

BEGIN SUBPROGRAM doStuff(first, second)
	second = first
END SUBPROGRAM

is equivalent to:

BEGIN MAINLINE
	a = "hello"
	b = doStuff(a)
	PRINT b
END MAINLINE

BEGIN SUBPROGRAM doStuff(first)
	RETURN first
END SUBPROGRAM

the question was hilariously vague, but your explanation for B,C,D being wrong was right and this stupid stuff makes A the most correct answer

 

[setonusyd]

Here is my multichoice:

1. A
2. C
3. D
4. B
5. B
6. C
7. D
8. D
9. B
10. B
11. C
12. A
13. D
14. C
15. B (Most people put B but looks like we may be wrong? My smart friend put A )...
16. B
17. C
18. A
19. C
20. D

 

[Handmedown]

I gather there will also be some controversy over Q23. b) iii.

Does the subprogram use reference parameters? If it does not then you would have to insert the code to display the swimmer's time inside the subprogram after the loops (which is probably not very good abstraction/programming technique), as the values in mainprogram will not have changed from -1.

 

[danny_2132]

1 a
2 c
3 d
4 b
5 b
6 c
7 can remmber which one i chose><<<<
8 d
9 b
10 b
11 c
12 a
13 d
14 c
15 b
16 b
17 b
18 a
19 c
20 a


omg the last question took me like 20 mins to figure out and it was soo fuken easy!!!!!!!!!!!!!!!!!!!