Section I - Multiple Choice (1 Viewer)

DJ696

Member
Joined
Feb 23, 2013
Messages
324
Gender
Male
HSC
2013
Guys im overthinking question 18, say you had two dice, say one is dice a and one is dice b
Combinations could be
1a+5b
2a+4b
3a+3b
4a+2b
5a+1b
But if were saying that 2a+4b and 4a+2b are two different things shouldnt it also include 3a+3b as being different to 3b+3a?
Hence 6/36 = 1/6, (A)
Its D because if you draw up a table of 1-6 on the left hand side and 1-6 on the top then you plus the numbers with left and top for all 3 numbers, there is only 5 numbers that add up to 6 making it 5/36 :)
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top