Yep. I got 4.5According to my friend it was 4.5 lol
Yep. I got 4.5According to my friend it was 4.5 lol
Bugger, it is too :/According to my friend it was 4.5 lol
The answer to that one was point B on the graph, basically it asked you which one was the point of inflection. Which I didn't know until I went and asked my Maths teacher after the exam. And I got it wrong. But anyway.fucked up question 8 or 9 dont remember, it was the curve and which point is greater than 0 and equal to 0 , stupidest thing -.-
C is a point of inflextion as well as B. So goddamn confusing.The answer to that one was point B on the graph, basically it asked you which one was the point of inflection. Which I didn't know until I went and asked my Maths teacher after the exam. And I got it wrong. But anyway.
But it's a horizontal point of inflexion, so f'(x) = 0C is a point of inflextion as well as B. So goddamn confusing.
fkn ughhhhhhhhhhhBut it's a horizontal point of inflexion, so f'(x) = 0
Screwed up that question as well :/
Got confused with question 6. 10 is B.I put down 10 as (B)
10 is definitely D. By Newton's second law F=ma acceleration is interchangeable with force. If you act a force in a direction that is opposite to the currently velocity of a particle it will slow down. ie. If your chair is rolling forwards and someone pushes (accelerates) you in the opposite direction you will slow down.im pretty sure 10 was b
remember velocity = speed WITH direction
and -acceleration means negative/going down
so i think it's B
Is this in the 2U course?...10 is definitely D. By Newton's second law F=ma acceleration is interchangeable with force. If you act a force in a direction that is opposite to the currently velocity of a particle it will slow down. ie. If your chair is rolling forwards and someone pushes (accelerates) you in the opposite direction you will slow down.
Hahaha I was gonna say lol.Is this in the 2U course?...
No, but it's just a another way to put it because a lot of people don't understand that negative acceleration =/= decelerationIs this in the 2U course?...
You'd be correct ... if speed was a vector, speed is not a vector. The current speed of the particle is negative, if it has positive acceleration than speed is increasing. Velocity on the other hand would be decreasing.10 is definitely D. By Newton's second law F=ma acceleration is interchangeable with force. If you act a force in a direction that is opposite to the currently velocity of a particle it will slow down. ie. If your chair is rolling forwards and someone pushes (accelerates) you in the opposite direction you will slow down.
http://www.physicsclassroom.com/class/1dkin/u1l1d.cfmYou'd be correct ... if speed was a vector, speed is not a vector. The current speed of the particle is negative, if it has positive acceleration than speed is increasing. Velocity on the other hand would be decreasing.
(Nb. force, acceleration and velocity are vectors, speed is not. Vectors are defiantly in the syllabus. )
Okay, but the question didn't say that force was being applied on the particle?No, but it's just a another way to put it because a lot of people don't understand that negative acceleration =/= deceleration
And v < 0, so the particle is moving toward the origin.If a > 0, the particle is travelling at an increasing speed.
If v < 0, the particle is travelling towards the left (or towards the origin).
For questions like: for what values of x is f(x) is increasing, isn't it when f'(x) > 0 ?
look at v as f(x) and a as f'(x)
Since a [ f'(x) ] is > 0, v [ f(x) ] is increasing. So the speed is increasing.
Therefore, the particle is moving towards the origin at an increasing rate (or speed, whatever it was).
What's the answer?Okay, but the question didn't say that force was being applied on the particle?
I'm looking it a different way.
And v < 0, so the particle is moving toward the origin.
Screw this.
Another mark lost.
Another band down the drain.