He posted above the correct answer. If you don't understand it though, he just examed T30, saw it was 1+2+3+...+30, which in turn is the sum of an arithmetic progression with starting value 1, final value 30, difference 1, n=30.
Sn = (n/2)(a+l)
S30 = (30/2)(1+30) = 15x31 = 475