Should be easy question (1 Viewer)

[J-Wang]

is sin(2x+1)y the same as sin(2xy+y)?

 

[Shadowdude]

or

 

[J-Wang]

don't know. that's my problem. the question is literally just sin(2x+1)y. what would u interpret that as?

 

[Shadowdude]

y times sin(2x+1)

 

[iSplicer]

don't know. that's my problem. the question is literally just sin(2x+1)y. what would u interpret that as?

sin[(2x+1)y]

 

[Shadowdude]

y times sin(2x+1)

sin[(2x+1)y]

hmm

 

[iSplicer]

Carrotsticks? Drongoski?

 

[Shadowdude]

In this circumstance, I'd do the question both ways - and use the one that gives the nicer answer

 

[D94]

don't know. that's my problem. the question is literally just sin(2x+1)y. what would u interpret that as?

sin[(2x+1)y]

 

[Carrotsticks]

If Y is a coefficient, they would say Ysin(2x+1).

But since it is at the end of the 'angle', it is to be interpreted as sin(2xy+y).

This happens quite a lot in Trig Series problems when you have to deal with things such as:



Which is obviously:



As opposed to:

 

[Drongoski]

sin[(2x+1)y]

I think it is this.

 

[Shadowdude]

clearly the solution is: don't be cheap and use brackets

 

[iSplicer]

hmm

=P

 

[SpiralFlex]

Some textbooks put the secondary variable after the first when they mean times. Namely Terry Lees mechanics solutions. He puts omega squared after the trigonometric expression.

 

[IamBread]

I'd say sin[(2x+1)y]

 

[math man]

don't know. that's my problem. the question is literally just sin(2x+1)y. what would u interpret that as?

what is the exact question? it might help us better understand if we know the exact context, however just looking at that now i would agree with carrot.