It's not entirely all that simple. You have to know log integration to do it.Hi,
Can someone please help with this question.
Find the primitive of:
View attachment 24428
When I do it i get x^2 / 2 + C. However, the answers a bit different.
Thanks
No, because when you divide by that power, you are dividing by 0 (zero), but you can't do that. The answer is wrong or the question is wrong.Thanks for the reply's.
Lol where did the post by the greatestsimpson go? That was the answer lol.
The answer says X^2/2 + x + C
I don't think they expect us to use logs yet.
Perhaps you guys can see a fault in my reasoning.
I understand up to f'(x) = x + x^-1 .
So then when I integrate I raise the power by 1 right and divide by that power?
So therefore,
X^2 /2 + x^-1+1
X^2/2 +x^0? (-1+1=0?_
X^2/2 + 1 + C