Simple question please help (1 Viewer)

[FOB all the way]

This is a simple question but i think i am missing something and can not get the answer it is
the line y=mx is a tangent to the curve y=e^3x find m
the answer is 3e
thanks in advance

 

[FOB all the way]

please

 

[mcs-one]

m1m2=-1 ????? so it wud be =-1/e^3x

 

[DownInFlames]

This is a simple question but i think i am missing something and can not get the answer it is
the line y=mx is a tangent to the curve y=e^3x find m
the answer is 3e
thanks in advance

y = e^3x

y' = 3e^3x

I don't know what else you'd do here.

 

[ahhliss]

Is it possible to find it without being given any values of x or y?
Derivative is 3e^3x so isn't that what m is in terms of x's?

 

[FOB all the way]

i think i just worked it out, is my reasoning correct
y=mx
y'=3e^3x
m =3e^3x
e^3x=3e^3x
x=1/3
m=3e^3(1/3)
m=3e^1
m=3e

im not sure if that is the right working but it gives the right answer

 

[Cob-was-here]

i think i just worked it out, is my reasoning correct
y=mx
y'=3e^3x
m =3e^3x
e^3x=3e^3x
x=1/3
m=3e^3(1/3)
m=3e^1
m=3e

im not sure if that is the right working but it gives the right answer

Its right except for where you missed a spot, but i think it's just a typo:
4th line -> e^3x=3xe^3x

this is because y=mx...u forgot the x part

 

[FOB all the way]

yer stupid error any way thanks for your help