Solution stoichiometry help (1 Viewer)

[mgg20]

I have a question I need help with and I’m not sure on how to actually work it out.
The question is ‘solutions A and B are labelled ‘0.15 M CaCl2’ and ‘0.25 M CaCl2’ respectively. Both solutions contain the same amount of CaCl2. If solution A has a volume of 50mL, what is the volume of solution B?’
I’m not sure how to find the volume of solution B.
PLEASE HELP!

 

[qUiCkMaThS]

Use c1v1 =c2v2
So, 0.15 x 0.05 = 0.25 x v2
v2 = 0.03L = 30mL
Therefore, solution B is 30mL

 

[mgg20]

Use c1v1 =c2v2
So, 0.15 x 0.05 = 0.25 x v2
v2 = 0.03L = 30mL
Therefore, solution B is 30mL

Thank you for the help. This may seem like a stupid question, but where do you get 0.03/30mL from? I’m not very good with math so I’m just a little confused.

 

[qUiCkMaThS]

1L = 1,000mL therefore 0.03L x 1000 = 30mL

 

[mgg20]

1L = 1,000mL therefore 0.03L x 1000 = 30mL

No I understood that but I mean, where do you get the 0.03L from?

 

[qUiCkMaThS]

0.15 x 0.05 = 0.25 x v2
v2 = (0.15 x 0.05)/0.25 = 0.03