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sasquatch

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Could anybody help me on this question:

"If our galaxy, the Milky Way, is 20 kiloparasecs or 65,000 light-years in radius,how fast would a spacecraft need to travel so that its occupants can trael right across it in 45 years?"

I used length contraction and time dilation to try and find an answer.

For spaceship, to = 45 years

tv = 45 / root(1 -v2/c2)

For Earth, Lo = 65,000c years

Lv = 65000 root(1 - v2/c2)

then i combined using v= /\r / t but got something like 288c.
 

Riviet

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For a start, you need to use the diameter, not the radius of the milky way. So use 130 000 ly as the distance. If I figure it out, I'll post up my answer. :)
 

sasquatch

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I did something wrong before. And now i cant get any answer...
 

zeropoint

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One approximate method is just to assume that tv = 65 000 y, since the spacecraft is obviously traveling very nigh the speed of light anyway.

Then plugging into your time dilation formula

tv = 45 / root(1 -v2/c2)

you get

v/c = 0.9999997604.

If you strive for accuracy, the corrected value of tv is actually squareroot(65000^2 + 45^2). But the values of v/c are so close (the first difference occurs at the 13th decimal place) that this correction is hardly necessary.
 

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