The 2004 HSC - Mathematics Paper (2 Viewers)

amy_lou

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argh!! i completely stuffed the simpson's rule question up!! what did everyone else do this part??i went in there confident and came out that disappointed - there goes my prospects of getting a UAI of 85 or above!!!
 

Willmaker

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slammindas said:
ey wat did every1 get for the shaded area of question 8 b
I worked out the length of AB to be the square root of 153. I then worked out perpendicular distance from C to AB to be 30/(root 17). Times the two together and half then take away watever you got in part iv.

(root 153) x 30/(root 17) x 1/2 - 18 = 27
 

fr0ggy

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acmilan1987 said:
I think i did too. i got something very close but not exact, i think something like 1291/1296
yeah. that's what i got
 

jiegu

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yeah i gor 45-18 =27 too!
i use 1/2absinc - the part 4 answer.
 

amime

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Willmaker said:
I worked out the length of AB to be the square root of 153. I then worked out perpendicular distance from C to AB to be 30/(root 17). Times the two together and half then take away watever you got in part iv.

(root 153) x 30/(root 17) x 1/2 - 18 = 27
yupz that's wat i got!
 

acmilan

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fr0ggy said:
yeah. that's what i got
Finally someone agrees with what i got, it think there have been about three different answers so far for this question

Willmaker said:
I worked out the length of AB to be the square root of 153. I then worked out perpendicular distance from C to AB to be 30/(root 17). Times the two together and half then take away watever you got in part iv.

(root 153) x 30/(root 17) x 1/2 - 18 = 27
I got that too
 

Bi0mic

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i totalled myself in that area one :|, completely skipped the fact there was a triange and went for 2 integrals :( ...

the pressure of a test clouds my mind :p
 

becany

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yeh i got 27 as the shaded area..
as for 9b...isnt part i when t = 2?
and part ii...particle furthest from origin means that x is a stat pt?
that means v = 0?
and since we were given that initially it is at rest at the origin (ie t = 0, v = 0)...i put time is between 0 and 1...but now that i think about it..im not too sure anymore
 

Jennibeans

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Willmaker said:
What I did was find the probability of you getting higher that 45 which ended up to be:

(1/6 x 1/6) x (1/6 x 1/6) x 2 - 5x5 then 5x5 or 5x5 then 5x4 is the only way you could get higher than 45 so I then went 1-(that answer) which ended up to be 647/648. Of course I could be wrong but thats the way I did it.
OMG I got that answer too...woo hoo actually got something right...maybe
I did it 1 - P(>45) which was 1/648 so the answer I got was 647/648
 

becany

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oh one more question...what did ppl get for 6ii?
the ratio of MY:AC?
i got like...1/root3 : 2
 

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