Willmaker
Member
um....I thought you did maths?coroneos said:srsly 110/120.. is that 95?
um....I thought you did maths?coroneos said:srsly 110/120.. is that 95?
I think i got 27slammindas said:ey wat did every1 get for the shaded area of question 8 b
I worked out the length of AB to be the square root of 153. I then worked out perpendicular distance from C to AB to be 30/(root 17). Times the two together and half then take away watever you got in part iv.slammindas said:ey wat did every1 get for the shaded area of question 8 b
yeah. that's what i gotacmilan1987 said:I think i did too. i got something very close but not exact, i think something like 1291/1296
yupz that's wat i got!Willmaker said:I worked out the length of AB to be the square root of 153. I then worked out perpendicular distance from C to AB to be 30/(root 17). Times the two together and half then take away watever you got in part iv.
(root 153) x 30/(root 17) x 1/2 - 18 = 27
Finally someone agrees with what i got, it think there have been about three different answers so far for this questionfr0ggy said:yeah. that's what i got
I got that tooWillmaker said:I worked out the length of AB to be the square root of 153. I then worked out perpendicular distance from C to AB to be 30/(root 17). Times the two together and half then take away watever you got in part iv.
(root 153) x 30/(root 17) x 1/2 - 18 = 27
OMG I got that answer too...woo hoo actually got something right...maybeWillmaker said:What I did was find the probability of you getting higher that 45 which ended up to be:
(1/6 x 1/6) x (1/6 x 1/6) x 2 - 5x5 then 5x5 or 5x5 then 5x4 is the only way you could get higher than 45 so I then went 1-(that answer) which ended up to be 647/648. Of course I could be wrong but thats the way I did it.