Z zeropoint Member Joined Dec 10, 2003 Messages 243 Location Sydney Gender Male HSC 2004 May 23, 2004 #1 The interior angles of a triangle are x, 2x and 180-3x. The sides opposite x, 2x and 180-3x are of length a, b and c respectively. Prove c = (b^2 - a^2)/a Any help would be appreciated.
The interior angles of a triangle are x, 2x and 180-3x. The sides opposite x, 2x and 180-3x are of length a, b and c respectively. Prove c = (b^2 - a^2)/a Any help would be appreciated.
