http://prntscr.com/c7atjh It was in a quadratics test.
pikachu975 Premium Member Joined May 31, 2015 Messages 2,739 Location NSW Gender Male HSC 2017 Aug 18, 2016 #1 http://prntscr.com/c7atjh It was in a quadratics test.
integral95 Well-Known Member Joined Dec 16, 2012 Messages 779 Gender Male HSC 2013 Aug 19, 2016 #2 What I did was starting with an equation y = a(x+11)(x-11) and you get that f(-7) = f(7) = 3, use that to solve for a and sub in x = 0 for the maximum height.
What I did was starting with an equation y = a(x+11)(x-11) and you get that f(-7) = f(7) = 3, use that to solve for a and sub in x = 0 for the maximum height.
leehuan Well-Known Member Joined May 31, 2014 Messages 5,805 Gender Male HSC 2015 Aug 19, 2016 #3 The above method should work. I would've done it a tiny bit differently and considered f(x)=ax(x-22) though. f(4)=3 Then find f(11)
The above method should work. I would've done it a tiny bit differently and considered f(x)=ax(x-22) though. f(4)=3 Then find f(11)
S si2136 Well-Known Member Joined Jul 19, 2014 Messages 1,370 Gender Undisclosed HSC N/A Aug 19, 2016 #4 Is the answer 446.1875 m?
pikachu975 Premium Member Joined May 31, 2015 Messages 2,739 Location NSW Gender Male HSC 2017 Aug 19, 2016 #5 si2136 said: Is the answer 446.1875 m? Click to expand... Nope
D Drongoski Well-Known Member Joined Feb 22, 2009 Messages 4,255 Gender Male HSC N/A Aug 19, 2016 #6 Using Integral95's approach, identical to mine, should get 121/24 = 5.041666 ... metres.