# VCE Maths questions help (1 Viewer)

#### boredsatan

##### Member
1. How to find the turning point and type of turning point in the equation y = (2/3)x^4 + 1/3
2. how to find equation of axis of symmetry of y = (2/3)x^4 + 1/3

#### InteGrand

##### Well-Known Member
Re: maths questions help

1. How to find the turning point and type of turning point in the equation y = (2/3)x^4 + 1/3
2. how to find equation of axis of symmetry of y = (2/3)x^4 + 1/3
1) Turning point at 0, local minimum.

2) Axis of symmetry is the y-axis.

Method used: inspection.

#### boredsatan

##### Member
Re: maths questions help

2) My book said that the axis of symmetry is x = 0. Maybe my book's wrong?

#### disturb_equilibrium

##### New Member
Re: maths questions help

2) My book said that the axis of symmetry is x = 0. Maybe my book's wrong?

the y axis is x=0!!!

• InteGrand

#### boredsatan

##### Member
Re: maths questions help

the y axis is x=0!!!
Oh, right, I get it now, was just a bit confused before.

• disturb_equilibrium

#### boredsatan

##### Member
Re: maths questions help

What's the difference between the turning point and the stationary point of inflection?

#### Green Yoda

##### Hi Φ
Moderator
Re: maths questions help

What's the difference between the turning point and the stationary point of inflection?
A point where a function changes from an increasing to a decreasing function or visa-versa is known as a turning point (i.e. gradient =0) However with turning points the concavity remains the same. In a stationary point of inflexion the gradient is 0 but the concavity changes, thus not changing from an increasing to a decreasing function or visa-versa.

• BLIT2014

#### boredsatan

##### Member
Re: maths questions help

A point where a function changes from an increasing to a decreasing function or visa-versa is known as a turning point (i.e. gradient =0) However with turning points the concavity remains the same. In a stationary point of inflexion the gradient is 0 but the concavity changes, thus not changing from an increasing to a decreasing function or visa-versa.
So for x^2, x^4, x^6, x^8, etc, there's a turning point, and for x^3, x^5, x^7, x^9, etc there's a stationary point of inflection?

#### InteGrand

##### Well-Known Member
Re: maths questions help

So for x^2, x^4, x^6, x^8, etc, there's a turning point, and for x^3, x^5, x^7, x^9, etc there's a stationary point of inflection?
Correct!

#### boredsatan

##### Member
Re: maths questions help

Thanks #### boredsatan

##### Member
Re: maths questions help

How hard it to get raw 40 in vce maths methods?

#### Drongoski

##### Well-Known Member
Re: maths questions help

How hard it to get raw 40 in vce maths methods?
Very few here are familiar with the VCE. But I find the VCE Maths curriculum modern and progressive.

#### boredsatan

##### Member
Re: maths questions help

Find the values of m if (2m-3)x^2 + (5m-1)x + (3m-2) = 0 has 2 solutions

#### InteGrand

##### Well-Known Member
Re: maths questions help

Find the values of m if (2m-3)x^2 + (5m-1)x + (3m-2) = 0 has 2 solutions

Remember, if the given quadratic equation has two distinct (real) solutions for x, then its discriminant must be greater than zero.

#### boredsatan

##### Member
Re: maths questions help

Remember, if the given quadratic equation has two distinct (real) solutions for x, then its discriminant must be greater than zero.
I ended up getting 25m^2 - 10m + 1 - 4(6m^2 - 13m + 6)
= 25m^2 - 10m + 1 - 24m^2 + 52m - 24
= m^2 + 42m - 23 > 0

#### InteGrand

##### Well-Known Member
Re: maths questions help

I ended up getting 25m^2 - 10m + 1 - 4(6m^2 - 13m + 6)
= 25m^2 - 10m + 1 - 24m^2 + 52m - 24
= m^2 + 42m - 23 > 0

#### boredsatan

##### Member
Re: maths questions help

A piece of wire 12 cm long is cut into two pieces. One piece is used to form a square shape and the other a rectangle shape in which the length is twice the width.
a. If x cm is the side length of the square, write down the dimensions of the rectangle in terms of x
b. formulate a rule for A, the combined area of the square and rectangle in cm^2, in terms of x.
c. determine the lengths of the two pieces if the sum of the areas is to be a minimum.

#### kawaiipotato

##### Well-Known Member
Re: maths questions help

Last edited:
• BLIT2014 and InteGrand

#### boredsatan

##### Member
Re: maths questions help

Is it normal to find maths hard even after tution? I'm in this scenario

#### boredsatan

##### Member
Re: maths questions help

The graph of y = x^4 - 2x - 12 has 2 x-intercepts
a. construct a table of values for this polynomial rule for x = -3,-2,-1,0,1,2,3
b. Hence state an exact solution to the equation x^4 - 2x - 12 = 0
c. State an interval within which the other root of the equation lies and use the methods of bisection to obtain an estimate of this root correct to 1 decimal place

I get how to do part a and b, but i'm finding part c extremely challenging and confusing.