~ ReNcH ~
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From my recent Volumes exam:
The curve y=sinx is revolved about the line y=1. Use an appropriate slicing technique to find the volume of the solid of revolution formed by the portion of the curve from x=0 to x=pi/2.
Does this question imply that the volume is formed by rotating the area bounded by the curve y=sinx, x=0, x=pi/2 and the x-axis around the line y=1? Or is the volume obtained by rotating the area bounded by y=sin, x=0, x=pi/2 and the y-axis around the line y=1?
The curve y=sinx is revolved about the line y=1. Use an appropriate slicing technique to find the volume of the solid of revolution formed by the portion of the curve from x=0 to x=pi/2.
Does this question imply that the volume is formed by rotating the area bounded by the curve y=sinx, x=0, x=pi/2 and the x-axis around the line y=1? Or is the volume obtained by rotating the area bounded by y=sin, x=0, x=pi/2 and the y-axis around the line y=1?