W00t! I did question 10... (1 Viewer)

[+GriM ReApeR+]

hehehe...but failed all the other questions though

 

[The Bograt]

How did you do that?
I thought Q8-10 were horrible

 

[+GriM ReApeR+]

Q10 was a simple simpsons formula and lots of algebra, but yea Q8-9 sucked

 

[Xayma]

Lots of algebra, not really.

The last bit of question ten just involved a bit manipulation. 8 and 9 were easier still.

 

[The Bograt]

Yeah well I messed up 8 big time, and it took me like 45 minutes, 9 wasn't great either. I got some things, and I'll get marks for working, just couldn't finish them off like all the others...

 

[jhakka]

Question 10 was a bastard of a thing.

 

[cheers_big_ears]

question ten was fairly good
the only part i couldnt get was b)i show xy=1/2bc

even withou t that the rest was fairly straight forward
cosine rule here and there and tricky differentiation.

part a was simple


it was a 'no dramas' paper for me.

 

[disco_dave]

congrates... i had nothing. stared blankly for a while and gave it a go, vut it didnt get me far... im feeling quite depressed right now! grr

 

[Sweet_Lemon]

compare to last yrs...which one's harder???

 

[Shimtek]

Q10 was a simple simpsons formula and lots of algebra, but yea Q8-9 sucked

10 wasnt all that nasty but i couldnt do it t

i did a) i) though, the simpsons bit.. i think i ended up with 7/9 or something ... i suck at 9 and 10's

 

[cheers_big_ears]

compare to last yrs...which one's harder???

last years definately.

i think they made up for it this year by making a bit easier

 

[acmilan]

question ten was fairly good
the only part i couldnt get was b)i show xy=1/2bc

even withou t that the rest was fairly straight forward
cosine rule here and there and tricky differentiation.

part a was simple


it was a 'no dramas' paper for me.

Since Area(AST)=Area(BCST) then

Area(ABC)=2Area(AST)

1/2(bcsinA) = 2.1/2(xysinA)

1/2(bcsinA) = xysinA

hence xy = 1/2(bc)

 

[ShaunSmith]

w00t your a fagget die, thanks.
quesion 10 B) was the worst thing since the day before sliced bread.. or something!

 

[The Bograt]

question ten was fairly good
the only part i couldnt get was b)i show xy=1/2bc

even withou t that the rest was fairly straight forward
cosine rule here and there and tricky differentiation.

part a was simple


it was a 'no dramas' paper for me.

I think you used
A1 = 1/2 xy sin A
A2 = 1/2 bc sin A x 2 (since the area is split into 2, that triagle is both their areas)
cancel the sin A
A1: A2 = 1:2
=1/2

 

[jam3s]

fucken sad test the biggest bull shit qestion 9 and 10
fuck i hate that shit
stupit qestion 10 b..... fuck

 

[superbird]

10B iii was good. all u had to do was differentiate it twice and then sub in the x value

 

[cheers_big_ears]

Since Area(AST)=Area(BCST) then

Area(ABC)=2Area(AST)

1/2(bcsinA) = 2.1/2(xysinA)

1/2(bcsinA) = xysinA

hence xy = 1/2(bc)

thanks but i really dont care what the answer was anymore (cant change it even if i did)

besides it was only worth one mark

 

[xeriphic]

question ten was fairly good
the only part i couldnt get was b)i show xy=1/2bc

even withou t that the rest was fairly straight forward
cosine rule here and there and tricky differentiation.

part a was simple


it was a 'no dramas' paper for me.

for that one just equate the area together using 1/2absinC

2 x of the small area = total area then solve

I couldn't do that last two ahhhhhhhhh of ten, the rest was okai

 

[Komaticom]

So how'd you do the last part? I'm guessing I had to use all the formulae proven beforehand? I tried working backwards, to no avail. Bah, help.

 

[Sweet_Lemon]

last years definately.

i think they made up for it this year by making a bit easier

still tough onezz~~