q7 = direct application of F=BILSin@Sparcod said:Ok. How do you do 7?
Show us the techniques.
It can be worked out from Lenz's Law and eddy currents.brack777 said:For question 9 I found what looks to be the same generator on wiki http://en.wikipedia.org/wiki/Homopolar_generator But it says
If it is not using faraday's law why is it in the exam? lol i got it wrong, i put a
Agree for the most part, except 7, which is D, cause its perpendicular to the magnetic field (NOT at 45 degrees, as you would believe) and 15 is A, aluminium, worked out by using forumlas, (you get frequency as 1.6 and 2.5 eV, hence AlIrskin said:1. C - g varies according to Gm/r2 and G is the universal gravitation constant
2. B - when the centripetal force of the string is removed, the mass will move horizontally perpendicular to its centre of motion.
3. D - M-M experiment shows the constancy of speed of light which provides evidence for Einstein's theory of relativity
4. B - The only acceleration on a projectile is gravity (g) which remains constant
5. D - Using Kepler's ratios
6. A - The wire will rotate around the magnet in a clockwise direction (i think).
7. C - Using F = BIlsin@ where l is route 1.40 squared
8. A - Im not sure whether flux is maximum or minimum at 0 (possibly B)
9. B - Using right hand palm rule where force is in opposite direction of motion of disc. Therfore current runs from Y to X.
10. A - Not sure about this, something about changing magnetic fields
11. A - Braggs used X-ray crystallography/diffraction
12. C - F = qvBsin@ and F = 0 when velocity is parallel
13. D - Metal lattice does not vibrate as frequently so resuistance is decreased
14. C - Aliminum; E = 5000 Vm-1. So we need E = 10000. This occurs for both perspex and copper, but only copper is suitable
15. D - Im not sure on this one either. Using the wavelength we find that the freqeuncy corresponds to maximum KE for aluminium but work function has to be factored in to find maximum KE. ie. KE = hf - work function of metal
Let me know what you think of these answers. Im hoping for 12-13/15
Acceleration on earth, we take as a constant 9.8, (yes okay it varies over the earth, but at the point where its droped is a constant), so yes velocity increases, however gravity is always a constant 9.8, and seeing as the graph wanted is an acceleration-time graph, B shows the constant acceleration of gravity, untill it hits the beach, where there is no more acceleration, showing abrupt end...Edge_Head said:Can anyone explain Q4? i realise that is simple. But majority is saying B, i just dont see how it is, well i sorta do..... If it was thrown wouldnt that mean that acceleration increases? as it leaves the hand? i dont know, can any one lend some insight to this question??
please enlighten us helper ...helper said:It can be worked out from Lenz's Law and eddy currents.
Try thisbboyelement said:please enlighten us helper ...