Nope since the prefix eth- is 2 carbon and the general formula is CnH2n+1COOH n>0. Methanoic acid is n=0 which is H-COOH, then ethanoic acid is n=1 CH3-COOH
It wouldn't be ethanoic acid if it were C2H5COOH because this has 3 carbon molecules in it, where this one would be propanoic acid