x^(2/3) (1 Viewer)

[CrashOveride]

Originally posted by Estel
hmm

suppose x = a/b where a/b is negative
y = x^x
= (a/b)^(a/b)
= 1/[(a/b)^(|a/b|)]
= 1/[(|b|rt)(a/b)^|a|]
hence if a is odd b must be odd
and if a is even b can be either.

so x = -0.4 = -2/5 should work then.
Where's the fault in my logic?

Edit: I see. Cursed calculator.

Your last line should read:
y= 1/[(|b|rt(a/b))^|a|]

Maybe clearer with lil example:

x^2/3 = x^1/3²

So its the cube root of x, squared

 

[Estel]

So you take the root first.

That elucidates everything.
Thanks.