Polynomials Question (1 Viewer)

[cutemouse]

Hello,

Could someone please help me with this question?

Thanks

 

[lyounamu]

Hello,

Could someone please help me with this question?

Thanks

PART 1
p(x) = (x^2-a^2)Q(x) + px+q

when x = a
p(a) = pa + q ...(1)

when x = -a
p(-a) = -pa + q ...(2)

(1) + (2):

2q = p(a) + p(-a)
q = 1/2 (p(a) + p(-a))

and

(1) - (2):
p(a) - p(-a) = 2pa
p = 1/2a (p(a) - p(-a))

PART 2

REMAINDER IS px + q where
p = 1/2a (p(a) - p(-a))

and q = 1/2 (p(a) + p(-a))

when n = even postive integer
remainder = 0

when n = odd pos integer
remainder = a^n-1 x - a^n

EDIT: I cannot believe that I am doing maths question from this early morning @.@

 

[clintmyster]

EDIT: I cannot believe that I am doing maths question from this early morning @.@

and I cannot believe im reading it

btw OP where'd you get this question from?

 

[cutemouse]

lol, why do you want to know?

 

[clintmyster]

lol, why do you want to know?

sheer curiosity LOL

 

[cutemouse]

lol.. it's from the James Ruse 2004 Ext 2 Trial.

 

[lyounamu]

lol.. it's from the James Ruse 2004 Ext 2 Trial.

This question doesnt' seem to hold any characteristic of 4 unit maths though. At a first glance, you would think it is 3 unit....hm...interesting