Solutions (3 Viewers)

[Thecorey0]

THese are my solutions - well answers. Remember these are by a student, and aren't necessarily right. Tell me if there is something wrong, as there most probaby is. Sorry for the horrible format. It won't let my upload either.

1b) x= 4/3
1c) x=4, -6
1d) m=1
1e) θ=π/3
1f) x= 7.3891

2ai) sinx +xcosx
2aii) 2e^x(e^x +1)
2bi) 5x + c
2bii) -3/(x-6) +c
2biii) 77/3
2c) 10

3a) 588
3bi) 4x-3y -5
3bii) 2
3biii) (x-1)^2 + (y-3)^2 = 4
3d) 64500m

4a) 12
4b) k=2, -6
4cii) 1:2

5ai) y=-x/root(3) +1
5aii) 2root(3)
5bi) 1/3
5bii) 1/3
5biii) (2/3)^5
5ci) θ=2π/3
5cii1) 2π/3
5cii2) 2(π/3 +1)

6a) 2πroot(3)
6bi) k=ln2/1600
6bii t=2536
6ci) b=12, a=-1/20
6cii) d=16.2

7aii) t=ln4
7aiii) x= 7/8 + ln4
7bi) T=12
7bii) h=0.3 t=2pm
7biii) 6-10am

8ai) 3>x>-1
8aii) the gradient approaches 0
8bi) $349688
8bii) $2270
8biii) 179 months
8biv) $129966

9a) 91/216
9bi) $12800
9bii) $15160
9biv) x= 5/4 c=$12200
9bv) p straight to s

10f) 17/12 -2ln2

 

[SophJI]

Oh this is depressing
you made my day
waaaaaaaaaa

 

[Thecorey0]

Oh this is depressing
you made my day
waaaaaaaaaa

They maybe wrong...

 

[HTB]

off the top of my head (recalling the answers I wrote), they look about right

I also got something like that for the loan savings question and I was worried about that since the 2 people next to me got something else (one of them is ranked first in my school)

 

[ashokkumar]

3biii) x^2 + y^2 = 4

Isn't this circle's centre (1,3)

therefore:

(x - 1)^2 + (y - 3)^2 = 2^2?

 

[Thecorey0]

Yes. Edited.

 

[blackratpoo]

ok. i disagree 3 iii) equation of a circle. at a diff cente, you seem to think at origin??

5, ii) 1/3 also i put. worded wierdly though,
and is 9 v) really straight underwater. ??

 

[cdiddy7]

Is there anywhere I can get worked solutions?

 

[ashokkumar]

You forgot +C for 2bii LOL

 

[xFusion]

ok. i disagree 3 iii) equation of a circle. at a diff cente, you seem to think at origin??

5, ii) 1/3 also i put. worded wierdly though,
and is 9 v) really straight underwater. ??

OMG looking at the answer I just realised I didnt read 9(v) properly =.=
Friggn found the cost instead.. erghh :mad1:

 

[Bdogz]

For 4cii) i got the ratio as 1:1 since that is the only way you can prove that ABC can be divided into two isosceles triangles

 

[jordz007]

what was the question for 2 b) iii)??
Thanks

 

[carlytse621]

for 9bii, isn't we times $1000 with the distance PS?
since we times 1000 from R to S, so P to S shouldn't be 1000 as well?
I am scare :S

 

[ashokkumar]

what was the question for 2 b) iii)??
Thanks

2bii)

Integrate: 3 / (x -6)^2

 

[jordz007]

2bii)

Integrate: 3 / (x -6)^2

No, b part three (iii).

 

[carlytse621]

No, b part three (iii).

integrate x^2 + root x dx from 1 to 4

 

[Thecorey0]

for 9bii, isn't we times $1000 with the distance PS?
since we times 1000 from R to S, so P to S shouldn't be 1000 as well?
I am scare :S

9bi) cost = 1000*5 + 2600*3 = 12800
9bii) cost = 2600*root(25+9 = root(34) *2600 =15160

 

[Currlz]

8ai) 3≥x≥-1

Would it not be 3>x>-1?

At -1 and 3 it will be 0?

 

[carlytse621]

9bi) cost = 1000*5 + 2600*3 = 12800
9bii) cost = 2600*root(25+9 = root(34) *2600 =15160

why X2600 for 9bii?
if we times 1000 from R to S, Q to S
then isn't we should times 1000 from P to s as well?

 

[Bdogz]

For 4cii) i got the ratio as 1:1 since that is the only way you can prove that ABC can be divided into two isosceles triangles

Can anyone confirm me please?