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unusual graph-please help (2 Viewers)

chrisnumber1

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why dont you do y=1 +3/(x-1)....and it should have an asymptote at x=1 and as x approaches infinity y should approach 1
 

kr73114

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why dont you do y=1 +3/(x-1)....and it should have an asymptote at x=1 and as x approaches infinity y should approach 1
excuse me, i know that x+2/x-1 is the same as 1 +3/(x-1)
how did u actually get to that?
 

hscishard

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It's a hyperbola.

Vert. Asymptote is x=1
Horizon Asymptote is y=1

Domain: All real x, x is not 1
Range: All real y, y is not 1

As x-> infinity, y-->1
As x -> -infinity, y--> 1 bottom side.

Y intercept at -2
X intercept at -2
 

YannY

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apparently it is, thats why i deleted my post.
 

madsam

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excuse me, i know that x+2/x-1 is the same as 1 +3/(x-1)
how did u actually get to that?
Ha, lol, and the long division crap? i laugh at you all

x+2 = x-1 + 3

so (x+2)/x-1 = (x-1+3)/x-1 = 1 + 3/x-1
 

frenzal_dude

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y=x+2/x-1

what is the domain and range
everyone please remember to use brackets, what you have just written is this:

If you meant to write that then that's ok, but if you meant to write this: then you need to write it like this: (x+2)/(x-1)
 

cutemouse

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everyone please remember to use brackets, what you have just written is this:

If you meant to write that then that's ok, but if you meant to write this: then you need to write it like this: (x+2)/(x-1)
That's a very minor point.
 

madsam

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everyone please remember to use brackets, what you have just written is this:

If you meant to write that then that's ok, but if you meant to write this: then you need to write it like this: (x+2)/(x-1)

someone's a bit pedantic...
 

nikkifc

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He does have a valid point you know.
Yeah but we know what the OP means... although yes, you should technically do it.

But in all seriousness, the frenzal guy should focus more on getting his mathematics up to scratch, rather than worrying about crossing his t's and curving his l's etc... they're very minor points...
 

hscishard

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If you really want to be that pedantic; you didn't quantify what 'k' is. ie, is 'k' a function of x, or a constant, or...?
Where k is a constant.

So yea, hows that?
Even if you did get k is a constant, I doubt you'll get correct answer without posting both solutions.
 

nikkifc

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Where k is a constant.

So yea, hows that?
Even if you did get k is a constant, I doubt you'll get correct answer without posting both solutions.
You obviously did get my point. My point was that you were being a pot calling the kettle black. If you were so perfect and so on, then you would've defined everything in your post, but you didn't so it shows something about you :)
 

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