Preliminary mathematics marathon (1 Viewer)

[SpiralFlex]

^ yep trial and error until it equals to 0 and use polynomials. Can't think of any easier way.

Which question are you referring to?

 

[Alkanes]

uhh i think that person deleted the comment or its gone somewhere :S

 

[SpiralFlex]

uhh i think that person deleted the comment or its gone somewhere :S

Must have known I was coming.

 

[Alkanes]

Yea lol.

 

[Hermes1]

can someone plz start a hsc trial mx1 and mx2 thread

 

[powlmao]

can someone plz start a hsc trial mx1 and mx2 thread

You can

 

[Hermes1]

You can

i no but if someone like ohexploitable does it more ppl r likely to contribute, bcuz then it looks like a legit thread

 

[powlmao]

i no but if someone like ohexploitable does it more ppl r likely to contribute, bcuz then it looks like a legit thread

True

 

[bleakarcher]

eyy, hscishard the answer given to ur question on the first page is in fact correct
u can verify and i got the same answer

 

[bleakarcher]

Find the equation of the cubic curve which has a maximum point (-2,-5), minimum point of (1,12), passing through the y-axis at the point (0,5)

 

[nightweaver066]

Find the equation of the cubic curve which has a maximum point (-2,-5), minimum point of (1,12), passing through the y-axis at the point (0,5)

Do you mean minimum of (-2,-5) and maximum of (1,12)?

If so,


Question:



Find p in terms of x and hence find p such that

 

[Hermes1]

Do you mean minimum of (-2,-5) and maximum of (1,12)?

If so,


Question:



Find p in terms of x and hence find p such that

p = x

hence p = 2

 

[Alkanes]

arj how would u do this? i have no clue

Find x

 

[Hermes1]

arj how would u do this? i have no clue

Find x

woh were did u get that question

 

[Alkanes]

somewhere i forgot but i wrote it down on my book..

 

[funnytomato]

somewhere i forgot but i wrote it down on my book..

are you sure you copied it down correctly ?

 

[deterministic]

arj how would u do this? i have no clue

Find x

I'm pretty sure you mean
In that case:

Solving gives
(Discard negative root of quadratic)

 

[funnytomato]

I'm pretty sure you mean

nice solution

but i wouldn't think that's in the mx1 syllabus

 

[ohexploitable]

can someone plz start a hsc trial mx1 and mx2 thread

i've already made one a while ago

http://community.boredofstudies.org/showthread.php/254512-HSC-Mathematics-Marathon

it's both 3u and 4u

 

[Saturn WY15]

Prove
(sin 150 + cos 270 + tan 315 )^2= sin^2 135 cos^2 225

Just wondering is there are faster method then finding the values of both sides then comparing ?