matchalolz
Well-Known Member
- Joined
- Feb 18, 2014
- Messages
- 1,179
- Gender
- Undisclosed
- HSC
- 2015
A certain integer is between 10 and 100. Its value is 8 times the sum of its digits and if it is reduced by 45, its digits are reversed. Find the integer.
So far I have:
8(x+y) = xy
xy - 45 = yx
however i don't think this is right because when i wrote xy i meant it as two digits next to each other but then xy is usually x multiplied by y.
anyone know how to do this?? thanks
So far I have:
8(x+y) = xy
xy - 45 = yx
however i don't think this is right because when i wrote xy i meant it as two digits next to each other but then xy is usually x multiplied by y.
anyone know how to do this?? thanks