mreditor16
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- Apr 4, 2014
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- HSC
- 2014
This was the method I was planning on using. Proving triangle AKM is similar to ABC, and then matching angles in the similar triangles would prove KM // BL. and matching sides in similar triangles are in ratio, thus KM = half of BC . and since BL = BC (i.e. half of BC is BL), KM = BLThink of it as similar triangles and matching sides would be in 1:2 ratio (midpoints)
It's a theorem you learn in 2U.
(hence proves the importance of 2U even if you do 4U)
lol looked through my notes, we never proved or touched this in class :/That is a legit theorem (I remember learning it in 2 unit maths).
If you have the Year 12 Pender book, you can find that theorem in there as well (page 332, of my copy at least).
Na. circle geo is useless.It's a theorem you learn in 2U.
(hence proves the importance of 2U even if you do 4U)
This was the method I was planning on using. Proving triangle AKM is similar to ABC, and then matching angles in the similar triangles would prove KM // BL. and matching sides in similar triangles are in ratio, thus KM = half of BC . and since BL = BC (i.e. half of BC is BL), KM = BL
therefore a pair of equal and parallel sides - thus, parallelogram.
but I don't know if BOSTES was expecting quite a long solution for the one mark.
lol looked through my notes, we never proved or touched this in class :/
I wonder whether BOSTES was really expecting us to remember that theorem? or they just wanted us to use the method I explained above. but it is a one mark "explain" Q, so idk :/
2006 HSCWhat year is this exam?
hmm so they were looking for Terry Lee's methodRight, cool.
Notes from marking centre:
"Of the few candidates who attempted this part, most gave unnecessarily lengthy arguments involving similar or congruent triangles. A few obtained the answer quickly by recognising the intercept property of lines through the mid-points of two sides of a triangle.
The most common mistake, among those who attempted this part, was to argue only that one pair of sides was parallel, or that one pair of sides was equal. Of course, many responses correctly observed that one pair of sides was both parallel and equal."
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really? just took a look at your solutions for the rectangular hyperbola 2013 hsc Q12 d) and it doesn't use it at all. :/This same property was used for also last year's rectangular hyperbola question.
oh yes my bad.I did for the very last part I believe.
I didnt use that.This same property was used for also last year's rectangular hyperbola question.