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KingOfActing

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I totally used pseudo-"inspection" to save time on 4U today.

It was one of those "Hence prove the the point T is T(..., ...)" which is done through simultaneous equations

I solved for y simultaneously, then just said "Substituting this back into the first equation gives x = [xcoord from question]" rather than actually dealing with the equation twice
 

Nailgun

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I totally used pseudo-"inspection" to save time on 4U today.

It was one of those "Hence prove the the point T is T(..., ...)" which is done through simultaneous equations

I solved for y simultaneously, then just said "Substituting this back into the first equation gives x = [xcoord from question]" rather than actually dealing with the equation twice
i do that in 2U lel
 

Paradoxica

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I totally used pseudo-"inspection" to save time on 4U today.

It was one of those "Hence prove the the point T is T(..., ...)" which is done through simultaneous equations

I solved for y simultaneously, then just said "Substituting this back into the first equation gives x = [xcoord from question]" rather than actually dealing with the equation twice
usually I consider the quotient and product of the x y co-ordinates... That's most of the "hard" locus questions.

The rest are impossible to see (and hence require magic) and the remaining are usually so obvious that the question can be handwaved in one line.
 

KingOfActing

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usually I consider the quotient and product of the x y co-ordinates... That's most of the "hard" locus questions.

The rest are impossible to see (and hence require magic) and the remaining are usually so obvious that the question can be handwaved in one line.
Oh no it was heaps easy, it's was just to prove that the coordinates were something. I think it was T(2cpq/(p+q), 2c/(p+q)). It was the point of intersection of the tangents at two points on a rectangular hyperbola. In the next part pq was assumed to be some constant (C) and so the locus is y = x/C
 

Green Yoda

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Curious: can I use matrices to solve simultaneous equations in my 2u exam? lel
 

Paradoxica

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Oh no it was heaps easy, it's was just to prove that the coordinates were something. I think it was T(2cpq/(p+q), 2c/(p+q)). It was the point of intersection of the tangents at two points on a rectangular hyperbola. In the next part pq was assumed to be some constant (C) and so the locus is y = x/C
that's so easy I laugh.
 

Paradoxica

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Curious: can I use matrices to solve simultaneous equations in my 2u exam? lel
LOL

I know you can use Matrices to solve problems of the Conic sections in 4U (source: Olympiad tutor)

I'm not sure 2U affords students the same flexibility.
 

leehuan

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Curious: can I use matrices to solve simultaneous equations in my 2u exam? lel
Wow gees your simultaneous equations in 2U aren't even hard and you want matrices?!
 

InteGrand

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LOL

I know you can use Matrices to solve problems of the Conic sections in 4U (source: Olympiad tutor)

I'm not sure 2U affords students the same flexibility.
Are you sure you're allowed to use matrices for the Conics section in HSC? Because that'll really trivialise some of the questions they ask.
 

KingOfActing

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LOL

I know you can use Matrices to solve problems of the Conic sections in 4U (source: Olympiad tutor)

I'm not sure 2U affords students the same flexibility.
SCREAMS

WHAT

That's so much easier I'm literally sobbing inside I wish I knew this eariler
 
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