Mathematics Predictions/Thoughts (3 Viewers)

[Saturday]

This is how I did it (attached). It was definitely tricky but I stared at it during reading time and it somehow clicked

Nice, that's also good. Avoids having to use parallel lines (like I did in my solution) which are a bit tricky to give a reason for.

 

[anerd]

I think these are the answers to the MCQ. I thought they were kind of tricky for a 2U paper. Sorry, no working:

1. B
2. D
3. B
4. C
5. A
6. C
7. D
8. C
9. A
10. B

is the answer to 10. B? because that's suggesting that it's stationary BETWEEN those points instead of at them. Isn't it C?

 

[StudyOnly]

I think these are the answers to the MCQ. I thought they were kind of tricky for a 2U paper. Sorry, no working:

1. B
2. D
3. B
4. C
5. A
6. C
7. D
8. C
9. A
10. B

Isn't 10. C because you go from positive gradient ot negative

is the answer to 10. B? because that's suggesting that it's stationary BETWEEN those points instead of at them. Isn't it C?

Ye I agree

 

[Saturday]

You're quite right, it is C. I misread the question.

 

[Saturday]

Alright, I'm going to go to sleep before I make any more mistakes. Best of luck for the rest of the HSC everyone!

 

[justtrynapass]

Did anyone else use sine rule for 14c? I haven't seen anyone who said they did - it gave the right answer though.

 

[BMWM2]

found the paper enjoyable - did all questions but the h=pq one in q15 - was pretty fair and would say it was a bit harder than 2018 - hopefully aiming for 88-92

 

[BMWM2]

Did anyone else use sine rule for 14c? I haven't seen anyone who said they did - it gave the right answer though.

yes i did and got the correct answer

 

[Husky]

So what does everyone think band 6 cut off will be?

 

[Hscbuzman]

So what does everyone think band 6 cut off will be?

85

 

[StudyOnly]

Does everyone think it was harder than previous years or easier?
I can't really tell, some part were harder than previous years and other were easier.

 

[sniggledot1]

in comparison to 2018 where b6 cutoff was 80, i believe ours will be around that 78-83 mark

 

[tywebb]

Solutions jointly by fun_jirachi and ruiace attached

 

[Hscbuzman]

Does everyone think it was harder than previous years or easier?
I can't really tell, some part were harder than previous years and other were easier.

Easier

 

[StudyOnly]

Resources

ngoandsons.com.au

Solutions from Ngo and Sons

 

[Hscbuzman]

Resources

ngoandsons.com.au

Solutions from Ngo and Sons

Well looks like I got 99/100 lol. I would have just lost one mark on MC 10 damnnnnnnnn

 

[TeheeCat]

Does everyone think it was harder than previous years or easier?
I can't really tell, some part were harder than previous years and other were easier.

Not the hardest paper of decade, 2013 still holds that title for me. I think its harder than 2018, though I do agree there's some parts easier/harder... Q16c of this year was pretty straightforward for me.

 

[Saturday]

Both the solutions posted above get 16(a)(ii) wrong, I'm pretty sure

 

[Makeanote]

Hi there group - here are my solutions for the exam - regarding Q16a(ii) (@ Saturday), I agree with the value, but as for being able to withdraw the FULL $80 000 as the question asks, I state 24 years. Also, the perimeter of the shaded area on the sector is incorrect in some working because of calculating in the wrong mode. A sector of 70 degrees (larger than an equilateral triangle) must have an opposite side longer than 20 cm (as given as the radius), so straight side AB is longer than 20 cm to begin with. Arc length AB must be longer still. But still, if there are any careless mistakes here, just let me know. It would have been a hot, difficult day for some students to concentrate for this one.
Ian

 

[Husky]

Hi there group - here are my solutions for the exam - regarding Q16a(ii) (@ Saturday), I agree with the value, but as for being able to withdraw the FULL $80 000 as the question asks, I state 24 years. Also, the perimeter of the shaded area on the sector is incorrect in some working because of calculating in the wrong mode. A sector of 70 degrees (larger than an equilateral triangle) must have an opposite side longer than 20 cm (as given as the radius), so straight side AB is longer than 20 cm to begin with. Arc length AB must be longer still. But still, if there are any careless mistakes here, just let me know. It would have been a hot, difficult day for some students to concentrate for this one.
Ian

Thanks for the solutions and yeah our supervisors only turned on the ac half way through the exam but by then it was too late since we were all sweating in our seats lol