How many 'words' from NONSENSE has a consonant as the first letter and a vowel as the last letter? (1 Viewer)

tk8

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Any help will be appreciated :)
 

icycledough

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So I think you can consider the different cases as mentioned above.

So if you have N,O --> you have N, N, S, S, E, E left. You can arrange this in (6! / [2! * 2! * 2!]) because of the repeated letters.

If you have N,E --> you have O, N, S, E, N, S left. You can arrange this in (6! / [2! * 2!])

If you have S,O --> you have N, N, E, N, S, E left. You can arrange this in (6! / [3! * 2!])

If you have S,E --> you have N, O, N, S, E, N left. You can arrange this in (6! / 3!)
 

tk8

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So I think you can consider the different cases as mentioned above.

So if you have N,O --> you have N, N, S, S, E, E left. You can arrange this in (6! / [2! * 2! * 2!]) because of the repeated letters.

If you have N,E --> you have O, N, S, E, N, S left. You can arrange this in (6! / [2! * 2!])

If you have S,O --> you have N, N, E, N, S, E left. You can arrange this in (6! / [3! * 2!])

If you have S,E --> you have N, O, N, S, E, N left. You can arrange this in (6! / 3!)
That cleared things up for me, thanks!
 

icycledough

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So I think you can consider the different cases as mentioned above.

So if you have N,O --> you have N, N, S, S, E, E left. You can arrange this in (6! / [2! * 2! * 2!]) because of the repeated letters.

If you have N,E --> you have O, N, S, E, N, S left. You can arrange this in (6! / [2! * 2!])

If you have S,O --> you have N, N, E, N, S, E left. You can arrange this in (6! / [3! * 2!])

If you have S,E --> you have N, O, N, S, E, N left. You can arrange this in (6! / 3!)
If you can double check as well that my reasoning is right, that would help. Perms and coms never used to be one of my strongest 3U topics.
 

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