MedVision ad

y = ln f(x) (1 Viewer)

Masaken

Unknown Member
Joined
May 8, 2021
Messages
1,725
Location
in your walls
Gender
Female
HSC
2023
is the above transformation tested in exams? (eg. given a curve f(x) drawn out, sketch the transformation y = ln f(x)?) it's not in the textbooks i use for school and i've only seen it appear in my tutoring qns and i think once in a school paper ages ago but that was it
 
Last edited:

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,391
Gender
Male
HSC
2006
In general, if you are given two graphs of y = f(x) and y = g(x) then you are expected to know how to sketch y = f(g(x)). See this year’s HSC for Advanced.
 

5uckerberg

Well-Known Member
Joined
Oct 15, 2021
Messages
562
Gender
Male
HSC
2018
In general, if you are given two graphs of y = f(x) and y = g(x) then you are expected to know how to sketch y = f(g(x)). See this year’s HSC for Advanced.
This is just from what I know the function of a function, replace with the equation given and then let f(...) where ... is the equation and then sub that new function into what is.
 

yanujw

Well-Known Member
Joined
May 23, 2020
Messages
339
Gender
Male
HSC
2022
is the above transformation tested in exams? (eg. given a curve f(x) drawn out, sketch the transformation y = ln f(x)?) it's not in the textbooks i use for school and i've only seen it appear in my tutoring qns and i think once in a school paper ages ago but that was it
It is not part of the further graphs topic set of transformations in ext 1, if that is what you meant.
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,391
Gender
Male
HSC
2006
This was in this year's Mathematics Advanced HSC.
1666793058157.png

In my mind, if a composite function graph is examinable in Advanced (which seems to suggest they can even ask to sketch y = ln f(x) in Advanced) what's the point of having all these below in Extension 1?
1666793226337.png
They are literally specific examples of y=f(g(x)) lol (albeit with inverse versions)
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top