I have no clue who you are. Please stop trying to socially engineer your way into being my friend pal1. Correct, you haven’t learnt proofs
2. It WAS in our trial
3. You don’t need to worry, cause you don’t even do 4u anymore
I have no clue who you are. Please stop trying to socially engineer your way into being my friend pal1. Correct, you haven’t learnt proofs
2. It WAS in our trial
3. You don’t need to worry, cause you don’t even do 4u anymore
mechanics -> just use the stuff on the last page of the formula sheet and common sensedoes anyone have like a summary sheet on mechanics and proofs?
For shm; max v at centre of motion (where a=0)??, max a at amplitudes of motion (where v=0)nahhh like when does max velocity, max acc. happen?
-7pi/12?
@carrotsss is this right??
also im assuming you guys liking this means that it was correct??For shm; max v at centre of motion (where a=0)??, max a at amplitudes of motion (where v=0)
I think
max velocity is at the centre of motion (look at the gradient of ur sin/cosine curve at ur centre of motion,you will notice it is the steepest)nahhh like when does max velocity, max acc. happen?
oh wait how did you get that-7pi/12?
A is amplitudemax velocity is at the centre of motion (look at the gradient of ur sin/cosine curve at ur centre of motion,you will notice it is the steepest)
max acceleration is happening at the extremities of motion: consider ur acceleration equation: a = -(n^2)(x-c), notice that when this value is a max it is at the points c + A and c- A
looks like you did except for the -9pi/12, that’s not how it works
looks like you did except for the -9pi/12, that’s not how it works
im a little confused as to how I convert 17pi/12
ohhhh is it just -2pi ???
yeah it isoh wait how did you get that
im a little confused as to how I convert 17pi/12
ohhhh is it just -2pi ???
i.e. (17-24)pi/12
17pi/12 is still within our desired principle argument raneg so i think its correct
yeah exactly if the argument is outside (-pi, pi] just add or subtract 2pi to keep it in the principle argument's range.ohhhh is it just -2pi ???
i.e. (17-24)pi/12
17pi/12 > pi which is outside the principle argument's range right?17pi/12 is still within our desired principle argument raneg so i think its correct
yeah true OKAY THANKSyeah exactly if the argument is outside (-pi, pi] just add or subtract 2pi to keep it in the principle argument's range.
17pi/12 > pi which is outside the principle argument's range right?
no but it also doesn’t really matter they wouldn’t mark you down for leaving it17pi/12 is still within our desired principle argument raneg so i think its correct
my mistake ur rightyeah exactly if the argument is outside (-pi, pi] just add or subtract 2pi to keep it in the principle argument's range.
17pi/12 > pi which is outside the principle argument's range right?