Maths Extension 2 Predictions/Thoughts (1 Viewer)

[TK123]

1. Correct, you haven’t learnt proofs
2. It WAS in our trial
3. You don’t need to worry, cause you don’t even do 4u anymore

I have no clue who you are. Please stop trying to socially engineer your way into being my friend pal

 

[ms_grape_taco]

does anyone have like a summary sheet on mechanics and proofs?

 

[carrotsss]

does anyone have like a summary sheet on mechanics and proofs?

mechanics -> just use the stuff on the last page of the formula sheet and common sense
proofs -> assuming u know all the basic stuff just bash it until something works idk

 

[SadCeliac]

Am I silly or have I done this correctly
Is e^i(17pi/12) = e^i(-9pi/12)???

 

[ms_grape_taco]

nahhh like when does max velocity, max acc. happen?

 

[SadCeliac]

nahhh like when does max velocity, max acc. happen?

For shm; max v at centre of motion (where a=0)??, max a at amplitudes of motion (where v=0)

I think

 

[shywa]

View attachment 40594
Am I silly or have I done this correctly
Is e^i(17pi/12) = e^i(-9pi/12)???

-7pi/12?

 

[SadCeliac]

View attachment 40594
Am I silly or have I done this correctly
Is e^i(17pi/12) = e^i(-9pi/12)???

@carrotsss is this right??

For shm; max v at centre of motion (where a=0)??, max a at amplitudes of motion (where v=0)

I think

also im assuming you guys liking this means that it was correct??

 

[SB257426]

nahhh like when does max velocity, max acc. happen?

max velocity is at the centre of motion (look at the gradient of ur sin/cosine curve at ur centre of motion,you will notice it is the steepest)
max acceleration is happening at the extremities of motion: consider ur acceleration equation: a = -(n^2)(x-c), notice that when this value is a max it is at the points c + A and c- A

 

[SadCeliac]

-7pi/12?

oh wait how did you get that
im a little confused as to how I convert 17pi/12

ohhhh is it just -2pi ???
i.e. (17-24)pi/12

 

[SB257426]

max velocity is at the centre of motion (look at the gradient of ur sin/cosine curve at ur centre of motion,you will notice it is the steepest)
max acceleration is happening at the extremities of motion: consider ur acceleration equation: a = -(n^2)(x-c), notice that when this value is a max it is at the points c + A and c- A

A is amplitude

 

[carrotsss]

View attachment 40594
Am I silly or have I done this correctly
Is e^i(17pi/12) = e^i(-9pi/12)???

looks like you did except for the -9pi/12, that’s not how it works

 

[SadCeliac]

looks like you did except for the -9pi/12, that’s not how it works

im a little confused as to how I convert 17pi/12
ohhhh is it just -2pi ???

 

[carrotsss]

oh wait how did you get that
im a little confused as to how I convert 17pi/12

ohhhh is it just -2pi ???
i.e. (17-24)pi/12

yeah it is

 

[SB257426]

View attachment 40594
Am I silly or have I done this correctly
Is e^i(17pi/12) = e^i(-9pi/12)???

17pi/12 is still within our desired principle argument raneg so i think its correct

 

[shywa]

ohhhh is it just -2pi ???
i.e. (17-24)pi/12

yeah exactly if the argument is outside (-pi, pi] just add or subtract 2pi to keep it in the principle argument's range.

17pi/12 is still within our desired principle argument raneg so i think its correct

17pi/12 > pi which is outside the principle argument's range right?

 

[SadCeliac]

yeah exactly if the argument is outside (-pi, pi] just add or subtract 2pi to keep it in the principle argument's range.



17pi/12 > pi which is outside the principle argument's range right?

yeah true OKAY THANKS

 

[carrotsss]

17pi/12 is still within our desired principle argument raneg so i think its correct

no but it also doesn’t really matter they wouldn’t mark you down for leaving it

 

[chilli 412]

 

[SB257426]

yeah exactly if the argument is outside (-pi, pi] just add or subtract 2pi to keep it in the principle argument's range.



17pi/12 > pi which is outside the principle argument's range right?

my mistake ur right

(this is the type of stuff i do in my exam and lose free marks to silly mistakes)