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$Would have been good to mention: $a=\frac{\sum F}{m}=\frac{T-mg}{m}$, but it will depend on your teacher I guess.

and ill pm you soon

Yeh sorry no crazy gypos allowed. you cant be trusted.

me and you need to talk business soon.

So isn't the quote referring to his increased word rate during study?

Good post, thanks

Wasn't that talking about how much he wrote during STUDY ??

It's probably better to think about things more than once,

Maybe post a question as an example?

Shit so did I :/ It should matter, unless the question already stated which way it was rotating?

If you're that sure, just put other preferences anyways, got nothing to lose.

You can change your preferences after atar comes out right?

yeep

It's not double the frequency. Once the threshold frequency is reached, increasing it even more makes no difference. Intensity controls the rate of emission of electrons, which is what current is: a rate. Hence A was the answer. Increasing energy is not increasing current.

Here at the 2013 trial thread, we don't use any existing functions... We're creating our own legacy. tn(x) reppin'

Why assume its with respect to x? Letterist.

howd you go? pm me

lol

If anything, that should make them produce a better paper, not copy past questions.

t=tan(x/2) not t=tan(pi/2) tan(pi/2) is undefined.