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Just wondering, did anyone whoever get a mark for answering 50kg in the first question?

Let me guess, the other subjects weren't too high scaling. Language subjects / economics / legal studies etc.. am I right?

Boo, it took me more than 4 minutes to type that up? Yep, i got 43.10527249, which is the same answer as fosweb's

First, draw a graph of x and y axis Y |-----/ A(x, y) |----/ |---/ |--/ |-/ 60 |/ B(a, 0) O``````````````````> X now, that 60 degrees is the angle of intersection. The rate of change of the distance of A from the centre is 40 km/h. The rate of...

I dont suck up to teachers, i just leave good impressions on them. i mean, turning up to 8:00 classes 15 minutes early would give a good impression, right?

only nike can save you.. just do it

I agree, this is reflected in the first question of the exam. im still waiting for the result tho..

87%, and top :D beaten no.1 by 12%, hopefully my total passes him, which means i'll be no.1 :D

b00 to CSSA exam paper, it's all stupid.

I don't quite understand the problem. Is this a complex number question?

of course you shouldn't care who comes first, with such a high mark everyone in your class will probably get band E4.. and average moderated assessment mark of 95 :D

could have been intentionally shown.. :p

CSSA right? pretty high marks you class got there..

that number is so sexy! I mean, 4unit student's won't know what a 69 position is, but they are sure to know 95+ position or 99 position..

oh sorry, it was meant to be ~79.9 UAI minimum or something :D :D :D

It seems that many people did not know yet that on average a student that does 4unit maths gets ~99.7 UAI.

oh ok. btw so far, the only use of calculus in binomials is for proving (1 + x)ⁿ derivatives / integrals patterns, where you have 1nc1 + 2nc2 + 3nc3 or nc1 / 1 + nc2 / 2 etc..

oiy, what's combinatorics?

28 marks? either you're that good or he was having a bad day, or both :D congratulations wow man... i'm below average if i was in your class..

First I considered the expansion of (1 + x)ⁿ = ⁿC₀ + ⁿC₁x + ... + ⁿC_nxⁿ I differentiated both side with respect to x, and got n(1+x)ⁿ = ⁿC₁ +...