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no, you dont need to know that. it was taken out of the syllabus when it was ammended. the teacher is a moron.:) we dont need to make any reference to wein's and the s-b laws.

lol did u notice the ;)? :p

haha yeh exactly, it was the first time i had been there. sif taking an hour bus ride:p

okay, in an attempt to answer your question after last night's appaling posts:). hmmm...actually i cant find a dot-point relating to that question. perhaps i have missed it, can you point it out. i have a slight feeling it isnt really in the ammended syllabus. as far as the dot points...

hhahaha i wagged religion today:D...i'm bad baby;):p wagging....its a pretty frequent thing for me. the school teaches jack shit

bah i'm not addicted, i dont know what your talking about, this 'addiction'....pfft ;)

oh my gosh! huy... hahahah this is a real shimmozzle(sp?) i should have included the likes of ;) and :p when i said, when did i say i'm not up for physics, i just dont know if i can explain it right now. when i initially posted, maybe if you put it in the physics section i thought that...

when did i say i'm not up for physics, i just dont know if i can explain it right now. in my last post i meant that maybe if you post this in the physics section, then perhaps someone else may answer to this post.

maybe if you put it in the physics section:)

yes i am indeed, why may you ask? funnniiiiii;)

bah, you are supposed to use it when dealing with chords. i dont know what i was thinking. havent done parametric for a while and that was one of the things i vaguely remembered from doing it. its something to remember, but then again you have to use it at the right time.

have some smilies been taken off? quite a few seem to be missing from the lot.

well done:) i should have known that, coz i've done similar q's before *dumbass* i even thought of that identity:chainsaw:

hmmm tricky one... x = t + 1/t dx/dt = ln(t) y = t^2 + 1/t^2 dy/dt = 2t - 2/t =(2t^2 - 2)/t^2 dy/dx = dy/dt / dx/dt = (2t^2 - 2)/t^2.ln(t) mmm...i have no idea really:p i'll leave this up, just in case it helps.

chech and chong its so shit, only the last few minutes of stand up/slapstick comedy was funny, but those few minutes were hillarious actually

yeh thanks:) you just need to incorporate S(k) result in the S(k+1) statement. you can work backwards, by placing the S(k) result in the S(k+1) statement(after factorisation) and working out an answer that way. thats the way i do it anyway.

have u tried the notes section on the main site?

whenever someone posts a helpful post, you give them a point or something. it encourages helpful posts. you actually click on a button to give them that point

assume: 5^n + 2 x 11^n =3I, I = 1, 2, 3.... consider n=1, 5 + 22 = 27 = 3I, where I=9 .'. true for n=1 assume n=k, consider n = k, 5^k + 2 x 11^k = 3I ** , I = 1,2,3... consider n = k+1 5^(k+1) + 2 x 11^(k+1)=3I =5^k x 5 + 2 x 11 x 11^k =5.5^k + 22.11^k =5(5^k +2.11^k) +...

hhaha i would have.....once upon a time.