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ah, i just took Spaz's answer for granted.. since it was the right eqaution. Well if you use calculus you get 112 as well.. So check your working again Spaz ^^. Problem solved. Thanks for the link wogboy, although im too groggy to understand any of that right now.

lol, yes thats a problem. But what i meant was.. if P(x) = (x-1)(x-2)(x-3) then (x-2)(x-3) divides into P(x) perfectly. So you sub in the product of those roots randomly just to make it work for laziness and simplicity's sake. What im saying is that the book is probably right, so if you get...

my side length was l = 1/4h + 8.. EDIT : Woops you're right its 8 - 6/4h. missed some numbers.

Im not sure what you mean?

I ussually start cramming a few days in advance.. but I don't feel i can study for physics anymore, i know everything so it just gets boring. Last year, I learnt the entire years work in a week because i never did anything the whole year... and i mean.. absolutely nothing.But i topped the grade...

I couldn't be bothered thinking about what the hell shape the first one is.. so i skipped it. Is the answer to the second one 325 1/3 units^3?

I don't see why you cant do it like the way its layed out. if A is a root and B is a root. Then AB is also a solution. as in, AB divides into P(x). Hence any product of two roots works with P(x). So just do that,, or you could expand it all and transmogrify everything until you end up with...

lol post HSC physics stress

The existentialism im familiar with is more a part of the 3u course. I think that existentialism is all about choice, in a world that lacks absolute meaning. As in, the only meaning you can get is what you make for yourself and in discovering yourself. In R&G, they are fated because they...

to this day, i dont know what general solution is.

The only thing i have to say for that is.. its hard. first, start with the result in part a(iv), and root everything.. and flip. then try and make that middle part equal to P_n and keep moving stuff around.

really? well okay, you have : u = (sinx^)n-1 u`= (n-1)cosx (sinx)^n-2 v = -cosx v`= sinx I-n = [-cosx(sinx)^n-1]pi/2 -> 0 + (n-1)Int{ (cosx)^2(sinx)^n-2 dx replacing cosx^2 with 1 - sinx^2 : I-n = (n-1) Int { (1 - sin^2(x))(sinx)^n-2 dx = (n-1) Int{ sin^n-2(x) -...

Or at the beginning you can split the (Sinx)^n into Sin^n-1(x) . Sin(x) and let dv/dx = sin(x) and carry on from there. Totally useless since its about exactly the same as McLake's, but i just thought i'd let you know.

atomic oscillators, i.e. atoms that vibrate. Atoms that vibrate get excited and electrons jumps to high energy then falls back down to ground state and releases radiation.

well, the shift is proportional to the velocity of the source relative to Earth. The star rotates alot slower than it moves. So the spectral lines observed due to rotation are probably alot less shifted than the ones observed from translational movement. Other than that, i wouldn't have a...

In discrete values.

um I think what they mean by that is how they overcome communication difficulties. For example, larger satellite dishes, concentrating signals using dish shaped reflectors, using short wave microwaves to penetrate, good and accurate equipment e.t.c

i had to match the rgb values to hex values for this, and now you tell me all i had to do was quote. lol. Oh so they have the internet on computers now..

Question 1 (a) Let u=tanx du=sec^2(x)dx Int{pi/4 -> 0}(tanx)^3(secx)^2 dx = Int{1 -> 0} u^3 du =1/4 Thats it for now. Catch next week's installment of 2001 HSC Solutions

HOLY CRAP im buying THAT house. although i would liek to have a bigger yard.