2001 HSC Solutions (1 Viewer)

[fashionista]

Hi!
Does anyone have or know where i can find the solutions to the 2001 HSC? cuz i cant find them anywhere at all

Thanx for ur help
luv me

 

[mojako]

Mission: to bring forth this thread from the grave...
True mission#1: to provide solutions to 2001 HSC ME3 paper, currently available from http:// home.exetel.com.au/winman/mathspapers/ex2/HSC2001solutions.pdf <==
True mission #2: to introduce invisible text

Disclaimer: please don't get angry at me for not posting anything useful
True disclaimer: I made the solutions and hence, by inspection, they may not be 100% correct.

Request: can anyone do the solutions for fashionita?
True request: well, I'm not specifically requesting, but if you find any error please let me know.

 

[Rorix]

Can I do them by inspection?

 

[mojako]

What do you mean??
I suppose so.. LOL... actually I use that word a couple of times in my answers...

 

[Slidey]

I'll do them all by inspection for you now, fashionista. Hang on, I'll be a few million seconds.

 

[mojako]

I'll do them all by inspection for you now, fashionista. Hang on, I'll be a few million seconds.

Oh I think it's been a few hours
Have you finished??
Hurry...

 

[McLake]

I should close this, but I eargly await Slide Rule's "by inspection" answers ....

You have have finished any proofs yet.

Prove LHS = RHS
"By insepection, LHS=RHS".

 

[Jase]

Question 1

(a) Let u=tanx du=sec^2(x)dx

Int{pi/4 -> 0}(tanx)^3(secx)^2 dx = Int{1 -> 0} u^3 du
=1/4

Thats it for now. Catch next week's installment of 2001 HSC Solutions

 

[mojako]

so since there are... hmm... 25 letter-parts in this paper, it will take 25 weeks for the complete solutions to become available in this forum
and that's the letter-part... the (a), (b) etc
there are some parts that contain numerical (or rather semi-letter) parts like (i), (ii), (iii)
and Question 1 part (a) happens to have no numerical part
so let's hope that Jase will give solution to one letter-part each week, not numerical-part.

Oh, if you close this thread, there's a good chance that I'll remove the solutions
oh wait.. I mean, I'll remove Jase's solutions by hacking.

 

[mojako]

I should really post this two days later, on the 9th of October.
But I can't wait...

Question 1
(b) Completing the square, x^2-4x+1 = x^2-4x+2^2 - 3 = (x-2)^2 - 3

Int 1/sqrt(x^2-4x+1) dx
= Int 1/sqrt((x-2)^2 - 3) dx
= ln ( (x-2) + sqrt((x-2)^2 - 3) ) + C
using the table of standard integrals.

Thats it for now. Catch next week's installment of 2001 HSC Solutions

 

[cj_bridle]

isnt this exciting.. i cant wait to see what mr integration gets up to next week.. will it be a sexy love triangle with mrs mechanics and mrs circle geometry?