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If f(x) = 4x9-3x8+9x7-5x6+x5-3x4+6x3-3x2+10x-13 find f''''''''(x) (the 8th derivate).

(a) 3125 ways in which the courses can be chosen i.e. (5C1)5 4C1*(5C1)4*5 ways in which one of the main courses is not chosen by any person = 100 100/3125 = 4/125 --- I hope this is right. (b) [nC1*(nC1)n-1*n]/(nC1)n *Crosses fingers.* Maths is so hard.

Elated but slightly regretful. Elation: more study time and chose the more challenging subject to keep. Regretful: I was going well in the subject (coming 1st) but chose the harder subject over it.

Discriminant > 0 4k2-4k-8 > 0 * k2-k-2 = 0 (k-2)(k+1) = 0 k = -1, 2 Sub in k = 0 into * -8 > 0 False Therefore k < -1, k > 2

I strongly disagree.

No. I tried really hard.

Belonging is the physical, psychological or spiritual acceptance of an individual into an existing entity ---> Maybe?

I hope you're right.

Anyone else struggling to keep up with the year 12 work? It's getting so tough to hold it all together and its only week 2. :o

Hello Jason. :) p3+q3+r3 = (p+q+r)3 -3(p2q+p2r+q2p+q2r+r2p+r2p+r2q) Wait, that didn't help. :(

First things first there's no guarantee. Second, when you get an answer to an equation, substitute it back into the original equation. Third, get a realistic answer. Fourth, check that you've answered the question. Fifth, don't take short-cuts in algebra - that way you are less prone to...

Nice work all. So many good results. The thing that annoys me is that we start afresh. :mad: I can't take any of my good ranks into HSC.

1*1 hour period + 2 lunchtimes per timetable cycle so far.

Next question: Trigonometric Functions (my favourite): (a) Prove (1+cosx+cos2x)/(sin2x+sinx) = cotx (b) Prove sqrt[(1-cosA)/(1+cosA)] = tan(A/2) and hence show that tan(pi/8) = sqrt(2)-1

Got report back: Subject - Cumulative Total - Cumulative Rank Studies of Religion 1 - 49/50 - 1/85 Mathematics - 96/100 - 1/28 Mathematics Extension 1 - 45/50 - 1/13 Chemistry - 80/100 - 2/18 Music 1 - 88/100 - 1/9 PDHPE - 90/100 - 1/17 English Advanced - 81/100 - 4/41

(1+ax)5 + (1+bx)5 = 1+5ax+10a2x2+10a3x3+5a4x4+a5x5 + 1+5bx+10b2x2+10b3x3+5b4x4+b5x5 = 2+30x+220x2... Equating coefficients: i) 5a+5b = 30 a+b = 6 10a2+10b2 = 220 a2+b2 = 22 ii) (a+b)2-2ab = 22 36-2ab = 22 2ab = 14 ab = 7 iii) a+b = 6 (1) ab = 7 (2) therefore a2-6a+7 = 0...

I'd have to say geometry.

3 in MX2. 12 in MX1. 7-8 in music. 10 in chem. 20ish in english. 15ish in religion. I like the class sizes I have.

http://community.boredofstudies.org/...d.php?t=185878 - my notes

MX2 - an hour period + 2 lunchtimes a timetable cycle