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There are a few ways to do this. I don't know if you know calculus yet (I'm assuming you would) but I'll do it without calculus just it case: f(x)= 17+4x-x^2 f(x)= -(x^2-4x)+17 f(x)=-(x^2-4x+4)+17+4 f(x)= -(x-2)^2 +21 Now notice that any number squared must be positive. Therefore the smallest...

Is this your prepared response or how much you want to write on the day? If you're fast, in 45 minutes you could hit above 1200 words in the actual test though most people wouldn't write this much. When preparing though, write less because you need to write an intro etc. that suits the question...

Check this out: http://www.wolframalpha.com/input/?i=plot+y%3Dsin2x-sinx+from+x%3D0+to+x%3D4pi

I don't know why everyone is complaining about MC. You treat it like any other question- look at it and then answer it. The only difference is that when you reach your final answer, you circle a box that has that answer (this also means that if you make a horrible mistake, the answers might tell...

Look at it like this. (-x)^2 is positive. (-x)^3 is negative. In general, (-x)^2n is positive whilst (-x)^2n+1 is negative. The reason it is undefined is because of the fact that is infinity even (therefore (-x)^infinity is positive) or odd (negative)?

This is good, just keep practicing. What I would do (I'm not sure if you do this now) is try and keep your working really organised so you know all the information you have and need. For example, for the above equation where you wanted the perp. bisector, you need both the gradient of that line...

96 needs a perfect UMAT. Not even 100th percentile- a perfect raw score iirc which is virtually impossible.

Yeah this. Why would you spend 10 minutes on a question if you haven't finished the paper?

No offence, but I think this is one of the worst examples of lack of bracketing I have ever seen in my life. Don't worry about the times symbol, enclose everything in brackets that goes together and please try reposting that.

Let u=tanx and go from there.

Yes, you should complain to someone. I don't know if the BOS is the right place (maybe somebody else can confirm/deny) but I would definitely get your parents to talk to the school. You might also want to ask the school if you can sit a new exam and see how you go in that.

Not if you don't get caught. And scanning wouldn't take long at all- I could do it at school in under an hour easy.

For d, both LHS and RHS are equal to one (using cosec^2-cot^2 and sec^2-tan^2). For g) cos^2(90-x)cotx=sin^2xcotx=(sinx)(sinx)(cosx)/(sinx)=(sinx)(cosx) -> The trick with this one is cos(90-x)=sinx

Re: HSC 2012 Marathon :) Consider A=5, B=2, B^A>A^B. Now consider A=3, B=2, A^B><b^a. now="" consider="" a="3," b="2," a^b="">B^A. Therefore conditions must be placed to satisfy the inequalities. Unfortunately I don't have time now to work it out- I'll try it tomorrow though because it looks...

For 2c) (secx)(cotx)=(1/cosx)(cosx/sinx)=1/sinx For 2i) 5(cot^2x+1)=5(cosec^2x) (on using cot^2x+1=cosec^2x) For 2l) cotx(1-cos^2x)=cotx(sinx)=(cosx/sinx)(sinx)=cosx Sorry about the lack of latex- I don't have much time now

Re: HSC 2012 Marathon :) How can you integrate e^ln(x) using this. If f(x)=ln(x), then f'(x)=1/x. Therefore to use this form, you would have to be integrating (1/x)(e^ln(x)) not just e^ln(x)

Re: HSC 2012 Marathon :) Ahh you noticed. I removed it because I didn't read your question properly and I didn't want to look like a retard if I was wrong. What is your question?

Re: HSC 2012 Marathon :) Yep. If you can though, try and learn to do these sorts of things without having to let u=whatever. Something like this you can just recognise after you do a lot of them which saves a lot of time in tests.

Re: HSC 2012 Marathon :) This isn't that hard is it? The left of the e is just the derivative of the exponent divided by 5.

Re: HSC 2012 Marathon :) Oooh, if you could find it, can you post it again. A nice question that I remember you posting was how to integrate 1/1+tan^n(x) between 0 and pi/2 but that needs 4U techniques...