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Because that's what it is. Tbh, I could probably learn more by just staying home and studying by myself but it'll be good to put names to faces, meet new people etc. Even if you sacrifice a day (which I won't because I'm planning on going to a few of the seminars), it'll still be worth going to...

I'll see what I can do. Not sure though if I can bring enough for everyone... (we'll have to keep it on the down-low). More relevant question, is everyone planning on doing their own study or more collective study/socialising?

If anyone wants to do something after, I was thinking of watching Spiderman so if people want to come, we could make it a thing...

This is a benefit not a cost. All the others are costs

This. I don't know why everyone simply assumes that natural ability doesn't exist and takes an idealistic view that everyone can get any ATAR. I go to a selective school so the general atmosphere in terms of studying and ATAR is pretty serious. There are large numbers of people that will study...

I've got exams this week. After exams, I'm planning on taking a one week break and then starting...

Hey guys, I was just looking at Euler's formula and came up with this: <a href="http://www.codecogs.com/eqnedit.php?latex=e^{i\pi}=-1\\ e^{2i\pi}=1\textup{ (On squaring)}\\ e^{2i\pi}=e^0\\ 2i\pi=0\textup{ (On equating powers)}\\ \therefore i\pi=0" target="_blank"><img...

Perfect score I think. Not expecting one obviously, a HD would be nice though... There was a kid in my primary though who got three medals in one year (WTF!!!)

Doing it tomorrow so it should be fun. Also, if you get a medal you get one bonus ATAR point at UNSW...

For 1) Note that tan(2x)=(2tanx)/(1-tan^2x) Your question fits this exactly -> (2tan(10))/(1-tan^2(10))=tan(2(10))=tan20 Sorry about the lack of latex - don't have time now.

I think the question is: <a href="http://www.codecogs.com/eqnedit.php?latex=\int x^2e^{x^3-1}dx" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\int x^2e^{x^3-1}dx" title="\int x^2e^{x^3-1}dx" /></a> Hint: Differentiate <a...

This isn't an area between two curves question. Consider the two areas (to the left of the point of intersection and to the right). -x is less than 1: The hyperbola has no influence on this. You are trying to find the area of the triangle bounded by the origin, x=1 and y=1 (intersection of line...

Let the roots be a,-a and b. a+(-a)+b=3 ->b=3 a(-a)(3)=-12 a^2=4 a=2,-2 Therefore the solutions are x=2,-2,3

This is true but you can still find sums and products for roots that aren't real. Consider the equation x^2+1=0. The discriminant is less than 0, therefore there are no real roots however the sums and products of roots gives us that the sum is 0 and the product is 1. When you do find the roots...

This is impossible to tell. Obviously above 98 given that 3 people get that but you could even get up to .95. It will all depend on how you go in your externals.

What school do you go to (give us the rank if you don't want to name)? The reason is that for example, at our school, they mark english very harshly (average is normally around 50-60%) even though we are a selective school and our HSC marks end up being much higher. Some of my friends schools...

Re: Atar estimate please :) Results for all exams/assessments included :) All welcom Can you clarify what you mean by selective school? The reason is that I go to a selective school and we don't have anyone doing gen. maths, CAFS etc, let alone almost 200.

Are you sure the first question is correct? The indefinite integral for your function is http://www.wolframalpha.com/input/?i=integrate+x%2F%282%2Bcosx%29 whilst the definite integral you provided gives a value of...

1. I go to a public school. A lot of my friends go to private schools (some elite and some 'ordinary'). Just going to a private school doesn't make you a douchebag and just going to a public school doesn't make you a hero. I know a lot of great people from both systems and I know a lot of drops...

I haven't tried it yet but I think you need to use the stronger form of induction i.e. assume true for n=k and all integers up to k (1,2,...,k) and then prove for k+1. I'll do it tomorrow if no one has done it by then.