An electron, accelerated from rest, reached a speed of 3x10^5 m/s in a distance of 0.25m under the influence of an electric field. Calculate the magnitude of the electric field strength.
Ok the answer is 6.4x10^-2 NC^-1
But i keep getting wrong answers.
v^2=u^2+2ar
so a=2x(3x10^5)^2
F=ma...