What I did was since the line y=mx+1 cuts y-axis at 1, therefore for it to have one solution, the gradient had to be equal or steeper then the right arm of the curve y=|2x-3|, which had gradient 2. The gradient cannot be negative because it will cut twice.
I got 95 in the CSSA trial for 2u and found it relatively easy, but yeah for people who are sitting there HSC this year for all subjects I can see where your coming from. I only have 2u and extension 1 to sit for this year and the rest of my subjects next year. So more time to prepare and revise.
It was 1/XY = 1/AD + 1/BC, but I used ratio intercept theorem parallel lines cut transversals in equal ratio or something like that and also the corresponding sides in the similar triangles and from there developed a relation. Don't have the diagram to explain, but that took me forever.
so r^2 = 12900t^2-18000t+10000, which is the same as 100(129t^2-180t-100). dr^2/dt = 100(258t-180), when dr^2/dt =0 t=30/43, finding d^2r^2/dt^2 = 100(258), therefore minimum for all values of t>=0. when t=30/43, r = 60.99942813, r=61 nearest km
I did a limiting sum, so Pat can win on his 1st, 2nd 3rd,... role. 1/36 + (35/36)^2(1/36) + (35/36)^4(1/36) + .... Factorise 1/36 out and you should get 1/36{1 + (35/36)^2 + (35/36)^4 +....). Sum to infinity, 1/36{1/(1-(35/36)^2)} = 36/71
It wasn't a difficult exam, just longer then the usual. 96 raw hopefully, but I screwed the volume question since I took the positive root 'y', also for absolute value one I accidentally wrote 0<m<=2 rather than m>=2 derp. Last part of last question took years to get out. The carp and trout...
Was pretty easy, no binomial identity and projectile theoretical problems =), got 2 replacement questions for binomial probability and binomial multiple choice question.