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  1. D

    General Thoughts: Mathematics

    Oh yes, you got me haha, m=-2/3 is the only other case.
  2. D

    General Thoughts: Mathematics

    Yeah, I remembered I solved a quadratic for n^2+43n-350=0 and you get n=7 n=-43, discarding the negative you get n=7
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    General Thoughts: Mathematics

    What I did was since the line y=mx+1 cuts y-axis at 1, therefore for it to have one solution, the gradient had to be equal or steeper then the right arm of the curve y=|2x-3|, which had gradient 2. The gradient cannot be negative because it will cut twice.
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    General Thoughts: Mathematics

    I got 95 in the CSSA trial for 2u and found it relatively easy, but yeah for people who are sitting there HSC this year for all subjects I can see where your coming from. I only have 2u and extension 1 to sit for this year and the rest of my subjects next year. So more time to prepare and revise.
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    General Thoughts: Mathematics

    It was 1/XY = 1/AD + 1/BC, but I used ratio intercept theorem parallel lines cut transversals in equal ratio or something like that and also the corresponding sides in the similar triangles and from there developed a relation. Don't have the diagram to explain, but that took me forever.
  6. D

    General Thoughts: Mathematics

    so r^2 = 12900t^2-18000t+10000, which is the same as 100(129t^2-180t-100). dr^2/dt = 100(258t-180), when dr^2/dt =0 t=30/43, finding d^2r^2/dt^2 = 100(258), therefore minimum for all values of t>=0. when t=30/43, r = 60.99942813, r=61 nearest km
  7. D

    General Thoughts: Mathematics

    I did a limiting sum, so Pat can win on his 1st, 2nd 3rd,... role. 1/36 + (35/36)^2(1/36) + (35/36)^4(1/36) + .... Factorise 1/36 out and you should get 1/36{1 + (35/36)^2 + (35/36)^4 +....). Sum to infinity, 1/36{1/(1-(35/36)^2)} = 36/71
  8. D

    General Thoughts: Mathematics

    It wasn't a difficult exam, just longer then the usual. 96 raw hopefully, but I screwed the volume question since I took the positive root 'y', also for absolute value one I accidentally wrote 0<m<=2 rather than m>=2 derp. Last part of last question took years to get out. The carp and trout...
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    HSC 2013-14 MX1 Marathon (archive)

    Re: HSC 2013 3U Marathon Thread Heres my solution to ^
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    HSC 2013-14 MX1 Marathon (archive)

    Re: HSC 2013 3U Marathon Thread ill just write up the solution, latex fail...
  11. D

    ellapls

    ellapls
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    noob

    noob
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    meanie

    meanie
  14. D

    HSC 2013-14 MX1 Marathon (archive)

    Re: HSC 2013 3U Marathon Thread Sketch the curve and develop and inequality, with x=pi and you should obtain that result
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    HSC 2013-14 MX1 Marathon (archive)

    Re: HSC 2013 3U Marathon Thread so i was right hah
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    CSSA Papers and their copyright.

    I didn't know that the replacement questions are gathered from other private papers so my bad =( since other schools haven't sat their trial yet.
  17. D

    CSSA MX1 Discussion Thread

    Same replacement questions ^ All the people in yr 12 screwed up =), even the 4u guys
  18. D

    CSSA MX1 Discussion Thread

    Was pretty easy, no binomial identity and projectile theoretical problems =), got 2 replacement questions for binomial probability and binomial multiple choice question.
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    Ghuy lol

    Ghuy lol
  20. D

    2013 CSSA Mathematics Thoughts?

    n=38 months since on the 37th month he still has more left to pay back
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