these questions pop up in the HSC a lot
let f(x) = 3x^2 - x^3
diff the function
dy/dx = 6x - 3x^2
solve dy/dx = 0 for stat points
hence x = 0, 2. for the y values sub this into f(x) {NOT dy/dx}
now for nature
d^2y/dx^2 = 6(1 - x)
subbing in x = 0 into d^2y/dx^2 we get a +ve value so it...